Answer:
If your on e2020, its C
Step-by-step explanation:
y^2=32x, the work above is correct but they forgot to take the square away in the final answer. hope this helps!
A function is a rule that assigns each vale of the independent variable to exactly one vale of the dependent variable.
The missing word is the function.
Point to remember:
The definition says that two values of x(independent variable ) may correspond to one value of y(dependent variable) but the vice versa is not true( means two values of y(dependent variable ) does not correspond to one value of x(independent variable) ). This explanation is very powerful tool to check that whether a relation is a function or not.
Answer:
12
Step-by-step explanation:
To find the value of k such that (k, k) is equidistant from (-2, 0) and (0, 5), we can use the distance formula.
The distance between two points (x1, y1) and (x2, y2) is given by the formula:
Distance = √((x2 - x1)² + (y2 - y1)²)
Let's calculate the distances from (k, k) to (-2, 0) and (0, 5) and set them equal to each other:
√((k - (-2))² + (k - 0)²) = √((k - 0)² + (k - 5)²)
Simplifying this equation:
√((k + 2)² + k²) = √(k² + (k - 5)²)
Squaring both sides of the equation to eliminate the square roots:
(k + 2)² + k² = k² + (k - 5)²
Expanding and simplifying:
k² + 4k + 4 + k² = k² + k² - 10k + 25
2k² + 4k + 4 = 2k² - 10k + 25
Rearranging terms:
4k + 4 = -10k + 25
Combining like terms:
14k = 21
Dividing both sides by 14:
k = 21 / 14
Simplifying the fraction:
k = 3 / 2
Therefore, the value of k that makes (k, k) equidistant from (-2, 0) and (0, 5) is k = 3/2.
a-4b
Simplify your answer as much as possible.
II
Х
?
Answer:
a+b2
a+4b
Now,
30+6×2
30-4×6
30+12
30-24
42
6