A man pushes on a box at an angle of 30.0° with a force of 20.0 N and the box moves across the floor. Which of the following component of the force do you use to calculate work?

Answers

Answer 1

Answer: Not sure what the given options are, but the answer is the horizontal component. This is given by Force x cos(angle), or Fcos(θ), where θ is the angle. In this case that would be 20cos(30) = 17.32N

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A hobo hops a freight train traveling at 2.5 m/s due east. The man boards the train from the rear of the boxcar and walks from the southwest corner to the north east corner of the car at a rate of 5.0 m/s. The boxcar is 15 meters long and 3 meters wide. What is the velocity of the man relative to the train tracks?

Answers

Since it isn't specified, I have to assume that when he's walking inside, along
the diagonal of the car, at 5m/s, that speed is relative to the floor of the car.
The reason I have to assume that is because I think it makes the problem
easier. I could be wrong. And it's still troubling, because 5 m/s is a hefty
11.18 mph, which is a pretty energetic walk. (In fact, it's a 5min 22sec mile,
which I for one never accomplished, even when I was running.) But so be it.

-- The length of the car's diagonal is √(3² + 15²) = √(9 + 225) = √334

-- The angle of his walk along the diagonal is the angle whose tangent is 3/15.

-- His velocity consists of the components [ 5 cos(angle) east ] and
[ 5 sin(angle) north ].

That's [ 5 x 15/√334 east ] and [ 5 x 3/√334 ] north .

The train's motion adds to the easterly component of his velocity,
and that becomes [ (2.5) + (5 x 15/√334) ] . The train's motion has
no effect on the northerly component of his velocity.

So now we're ready to put the components together and find his velocity
relative to the tracks. I think it'll be easier to go ahead and get the numerical
value of each component, and then combine them.

Easterly component: (2.5) + (5 x 15/√334) = 6.6038 m/s

Northerly component: 5 x 3/√334 = 0.8208 m/s

Just before finding the magnitude, we note that the direction of his velocity
is (the angle whose tangent is 0.8208/6.6038) north of east. That's about
7.085 degrees north of east ...the compass bearing of 82.92 degrees.

Now for the magnitude. It's the square root of the sum of the squares of
the easterly component and the northerly component.

√ (6.6038² + 0.8208²) = √44.2841 = 6.655 m/s

(All numbers are rounded.)

That's my story, and I'm sticking with it.

Why does it take less time for small rocks to wear away than it does for large rocks to wear way?

Answers

If you take one large rock it only wears away on its surface.

If you now break that rock in half the surface is the old outside AND the new break in half - therefore more surface area to wear away. Break these two halves again and there is more surface area to wear away.

Keep going and break your large rock into many pieces and you get small rocks which wear away much quicker.

It is because that small rocks are lighter than large rocks. It is hard for larger rocks because they are very heavy.

Romeo ( mass = 70 kg ) feels a gravitational attraction for Juliet ( mass = 50 kg ). If hey are 20 m apart, find the force.

Answers

What even is this question
Love? Idk lol

The variable that is observed or measured during an experiment is called what type of variable?a. independent
c. controlling
b. manipulated
d. dependent

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The correct answer for the question that is being presented above is this one: "d. dependent." The dependent variable is that one that is being measured in an experiment and which is influenced by the independent variable - the experiment measures the effect of the independent variable on the dependent variable.

Would a tiger be a consumer or producer?

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Tigers don't produce anything useful, but they are the top of their food chain. They would e top predators, and top predators are always consumers.

1. How does an area’s weather differ from the area’s climate? (1 point). A.Weather involves temperature and precipitation and climate involves only temperature.. B. An area’s weather depends on where it is located on Earth and the area’s climate does not.. C.An area’s weather does not change very much and an area’s climate changes many times.. D.Weather is the area’s day-to-day conditions and climate is the area’s average conditions.. 2. All of the following factors contribute to Earth’s climate EXCEPT (1 point) . latitude.. longitude.. transport of heat by winds.. shape and elevation of landmasse

Answers

An area's weather differs from an area's climate because weather is the area's daily conditions. The climate is the average conditions of the area.

Longitude does not contribute to the earth's climate. Longitude are imaginary lines that have no impact.

Weather is the area's day-to-day conditions, such as temperature and precipitation, while climate refers to the average conditions over a long period of time. All of the given factors contribute to Earth’s climate except longitude. The correct options are D and B.

A location's short-term atmosphericconditions, such as temperature, humidity, precipitation, wind speed, and air pressure, are referred to as the "weather."

Even within a single day, it might fluctuatedramatically from one day to the next. The long-term average weather patterns of a region are represented by climate, which often spans decades or centuries.

Latitude, wind-borne heattransport, form and height of landmasses, and all the other elements mentioned affect the climate of the planet.

Latitude has a big impact on how solar energy is distributed and how temperature patterns are affected.

The movement of heat by winds contributes to the distribution of heat and moisture around the world, which influences climate fluctuations.

Thus, the correct options are D and B.

For more details regarding precipitation, visit:

brainly.com/question/18109776

#SPJ6

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