How do you Factor this?
-8y^3( 7y^2- 4y - 11)
-8y^3 (7y-11) (y+1)
If the domain is restricted to the portion of the graph with a positive slope, how are the domain and range of the function and
its inverse related?
Since the domain of the original function is limited to x 6, the range of the inverse function is y s6.
Since the domain of the original function is limited to x> 4. the range of the inverse function is ys 1.
Since the range of the original function is limited to y > 6, the domain of the inverse function is x 26
Since the range of the original function is limited to y 4, the domain of the inverse function is x 1.
The answer is the statement Since the range of the original function is limited to y > 6, the domain of the inverse function is x ≥ 6.
The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.
The positive slope definition tells us that a line with a positive slope is one where the right side of the line is higher than the left side of the line.
So, by the definition given above, we see that
if the range of the original function is limited to y > 6, the domain of the inverse function is x >= 6.
Learn more about the domain of inverse functions on:
#SPJ2
Answer:
Since the range of the original function is limited to y 6, the domain of the inverse function is x ≥ 6.
Step-by-step explanation:
A. (2,4),(-2,-1), (-7,5)
B. (4,6),(-1,2), (5, -3)
C. (4,-2),(-1,2), (5,7)
D. (4,2), (-1,-2), (5, -7)
The book has these as the optional answers but I keep getting (-2,-4), (2,1), (7, -5)
Can someone help me??
Answer: (-2,-4), (2,1) and (7,-5)
Step-by-step explanation:
When rotating a point 180 degrees about the origin a point A(x,y) becomes A'(-x,-y).
When translating a point B(x,y) by 'h' units left, then the new point will become B'(x-h,y).
Given: A triangle with coordinates (6,4), (2, -1), and (-3,5) is translated 4 units left and rotated 180° about the origin.
Translation rule for 4 units left : (x,y) → (x-h,y)
The new coordinates will be (6-4,4) , (2-4,-1) and (-3-4, 5)
i.e. (2,4), (-2,-1) and (-7,5) .
Now, applying the rotation rule of 180 degrees we get the points of the final image as
(-2,-4), (2,1) and (7,-5) .
Hence, the coordinates of its image is (-2,-4), (2,1) and (7,-5) .