Convert 478 to number of hundreds, tens, and ones

Answers

Answer 1

Answer: 400 + 70 + 8
Because the 4 is in the hundred's place, the 7 is in the ten's place, and the 8 is in the one's place.

Answer 2

Answer: If you pût h above thé 4 wich stands for thé hundreds collum then a t under thé 7 for thé tend collum and you pût a u above thé 8 then you can see it easier

400,70,8

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Leo has a total of 45c. he has some dimes and pennies . How many different combinations of dimes and pennies could Leo have?make a table to solve.

Answers

4 dimes and 5 pennies

3 dimes and 15 pennies

2 dimes and 25 pennies

1 dime and 35 pennies

0 dimes and 45 pennies

5 is the answer

Giuseppi's Pizza had orders for $931.00 of pizzas. The prices were $21 for a large pizza, 514 for a medium pizza, and $7 for a small pizza. The number of large pizzas was two less than four times the number of medium pizzas. Thenumber of small pizzas was three more than three times the number of medium pizzas. How many of each size of pizza were ordered?

Answers

Answer:

Number of Large Pizzas: 30

Number of Medium Pizzas: 8

Number of Small Pizzas: 27

Step-by-step explanation:

L = # of large Pizzas

M = # of medium Pizzas

S = # of small Pizzas

Amount:

L = 4M - 2

S = 3M + 3

Cost:

21L + (I'm assuming you meant 14) 14M + 7S = 931

Plus in the Amounts to the Cost:

21(4M - 2) + 14M + 7(3M + 3) = 931

84M - 42 + 14M + 21M +21 = 931

Combine like terms:

119M - 21 = 931

Isolate the Variable:

119M - 21 + 21 = 931 + 21

119M = 952

119M/119 = 952/119

M = 8

Plug it into the Amount equations:

Large: L = 4(8) - 2

L = 32 - 2

L = 30

Small: S = 3M + 3

S = 3(8) + 3

S = 24 + 3

S = 27

Check your work (plug the values into Cost.):

21(30) + 14(8) + 7(27) = 931

630 + 112 + 189 = 931

931 = 931

Final answer:

The number of medium pizzas ordered was 10. Hence, based on the given relationships, the number of large pizzas was 38 and the number of small pizzas was 33.

Explanation:

To solve this problem, really, we are using three algebraic expressions that represent the total cost, the relationship between the large and medium pizzas, and the relationship between the small and medium pizzas.

We can define M as the number of medium pizzas, L as the number of large pizzas, and S as the number of small pizzas. We can then set up the following equations based on the problem:

$21L + $14M + $7S = $931
L = 4M - 2
S = 3M + 3

We can substitute equations 2 and 3 into equation 1 to get a single equation in terms of M:

$21(4M-2) + $14M + $7(3M+3) = $931

Which simplifies to:

93M = 931

Then, M=10, hence, the number of medium pizzas is 10, number of large pizzas (4M-2) is 38, and the number of small pizzas (3M+3) is 33.

Learn more about Algebra here:

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A cooking club has 10 members. how many ways can they select a president and vice president from among the members?A. 180
B. 20
C. 100
D. 90

Answers

There are 10 possible ways to select a president from the club, because their are 10 available members to choose from.

After a president is chosen, their are 9 possible ways to select a vice president, because one of the members will already have the position of president, so they can't be vice president (10-1=9)

Now we just multiply to possibilities of presidents by the possibilities of vice-presidents.

president*vicepresident=
10*9=90

Answer= D. 90

Jim, Carla and Tommy are members of the same family. Carla is 5 years older than Jim. Tommy is 6 years older than Carla. The sum of their three ages is 31 years. How old is each one them?

Answers

So,

We'll solve it with only one placeholder, since that's simpler.

Jim's age = J
Carla's age = C
Tommy's age = T

J = base
Carla's age = J + 5
Tommy's age = Carla's age + 6 or J + 5 + 6 or J + 11

Sum of ages = 31
(J) + (J + 5) + (J + 11) = 31

3J + 16 = 31

Subtract 16 from both sides
3J = 15

Divide both sides by 3
J = 5

Carla's age = J + 5
Carla's age = 10

Tommy's age = Carla's age + 6
Tommy's age = 10 + 6 or 16

5 + 10 + 16 = 31
15 + 16 = 31
31 = 31 This checks.

Jim is 5.
Carla is 10.
Tommy is 16.

lets
Jim x years old
Carla (x+5) years old
Tommy (x+5)+6 years old
sum is x+(x+5)+(x+5)+6=31 years old
3x+16=31
3x=15
x=5 - age of Jim
x+5=5+5=10 - age of Carla
x+5+6=16 - age of Tommy
Answer: 5, 10 and 16 y.o

Need help quick!! Please explain how you got your answer.