D1 = 35 md2 = 12 m

A= ________

Formula of a rhombus is A=1/2 d1 d2
what is the area??

Answers

Answer 1
Answer: a=1/2d1d2
plug in
a=1/2(35)(12)
a=210

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Answers

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PLEASE HELP AND ANSWER RIGHT AWAY! I'M TERRIBLE AT MATH!Jeremy ate 1 1/2 tacos at the birthday party. Cecilia ate 2 1/2 times as much as Jeremy.

How many tacos did Cecilia eat?
Express your answer in simplest form.

Answers

1 (1)/(2) = (3)/(2)\n\n2 (1)/(2) = (5)/(2)\n\n\n\n(3)/(2) * (5)/(2) = (3* 5)/(2* 2) = \huge{\boxed{(15)/(4)=3(3)/(4)}}

Every day, Jason runs for 34 minutes and lifts weights for 44 minutes. How many minutes will Jason spend working out in 7 days?

Answers

34*7=238
44*7=308
238+308=546
You add 34 and 44 and you get 78. Then you multiply 78 by 7. You should get 546. So Jason will spend 546 minutes working out in 7 days

If a baseball and a bat cost $1.10 together, and the bat costs $1.00 more than the ball, how much does the ball cost?

Answers

Contrary to the above answer, the ball does not cost $0.10! If the ball were to cost 0.10 then the bat must cost $1.00 which is only $0.90 more than the ball! We can solve this equation correctly using an expression like so:
b = price of the ball
b + 1 = price of the bat
b + (b + 1) = price of the ball + price of the bat
b + b + 1 = 1.10
Therefore reareanging the equation:
2b = 0.10
And therefore:
b = 0.05
So the ball costs $0.05 and the bat costs $1.05 :))

He has 72 pencils and 24 erasers and he must use all of the pencils and erasers. If dated creates the greatest number of identical packages possible, how many pencils would be in each package?

Answers

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Ron and Pam each have 20 pennies. Ron will put his pennies into 4 group.pam will put her pennies into 5 groups. Who will have more pennies in each group? Explain.

Answers

Hi there,

So lets look at this problem. Ron has 20 pennies. Pam has 20 pennies. If Ron has 4 groups each group will have 5 pennies to add up to 20. Pam will have 5 groups and each group will have 4 pennies to add up to 20.

Therefore Ron will have more pennies in his group.