Tile costs $28 per square meter. how much will it cost to cover the countertop with new tile? (48 square Feet)

Answers

Answer 1
Answer: You multiply 48 by28. You get 1344.So it would cost $1,344.00.

Related Questions

in this triangle, the product of sin b and tan c is , and the product of sin c and tan b is . nextreset
If E is on the interior of ∠ABD, m∠ABE = (2x - 5)°, m∠EBD = (x + 1)°, and m∠ABD = 50°, find the value of x.
Solve the system of equations below y=3/2x-2 and 2x+y=-4
What is the solution of the system? Use a graph. y = –3x + 2 y = –3x + 4
Write an equation of the line and interpret the slope.

Find solution to logarithm.

Answers

\log5x+\log(x-1)=2\n D:5x>0 \wedge x-1>0\n D:x>0 \wedge x>1\n D:x>1\n \log5x(x-1)=2\n 10^2=5x^2-5x\n 5x^2-5x-100=0\n x^2-x-20=0\n x^2-5x+4x-20=0\n x(x-5)+4(x-5)=0\n (x+4)(x-5)=0\n x=-4 \vee x=5\n -4\not \in D\Rightarrow x=5
log_pa=b\ \ \ \Leftrightarrow\ \ \ p^b=a\n\nloga+logb=log(a\cdot b)\ \ \ \Rightarrow\ \ \ D:\ a>0\ \ \ and\ \ \ b>0\n ----------------------------- \nlog(5x)+log(x-1)=2\ \ \ \Rightarrow\ \ \ D:\ 5x>0\ \ \ and\ \ \ x-1>0\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x>0\ \ \ and\ \ \ \ \ \ \ \ x>1\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=(1;+\infty)\n\nlog[5x\cdot(x-1)]=2\ \ \ \Leftrightarrow\ \ \ 5x(x-1)=10^2

5x^2-5x=100\ /:5\n\nx^2-x-20=0\n\nx^2-5x+4x-20=0\n\nx(x-5)+4(x-5)=0\n\n(x-5)(x+4)=0\ \ \ \Leftrightarrow\ \ \ x-5=0\ \ \ or\ \ \ x+4=0\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=5\ \ \ or\ \ \ \ \ \ \ \ x=-4\n\n5\in D;\ \ \ -4\notin D\n\nAns.\ x=5

Alex and ben go to a cafe with some friends. Alex buys 4 cups of coffee and 3cups of tea. He pays a total of £6.95. Ben buys 5 cups of coffee and 2 cups of tea. He pays a total of £7.20 Work out the cost of each cup of coffee and the cost of each cup of tea

Answers

c - the cost of one cup of coffee
t - the cost of one cup of tea
1.          (4c + 3t=6.95)*2     -----> 8c+6t=13.90   (1)
             (5c + 2t =7.20) *(-3) ---->-15c-6t=-21.60  (2)

2. Add equation (1) and (2)
             -7c= - 7.70,   c=1.10  Cup of Coffee  £ 1.10
3. substitute 1.10 into the first equation
4c + 3t=6.95,     4*1.10 + 3t=6.95,  3t = 6.95-4.40 =2.55,  t=  £ 0.85 cup of tea

A music festival charges $54 and 95 per ticket sold on the day of the event. A ticket purchased before the festival cost only $39.95. There were only 20,000 tickets sold for a total of $925,000 how many tickets did they sell at the music festival? How many tickets did they sell before the music festival?

Answers

b=number of ticets sold before
a=number of tickets sold after

cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a

total cost=925000
39.95b+54.95a=925000

total number tickets=20000
b+a=20000

we have

39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
-39.95b-39.95a=-799000 +
0b+15a=126000

15a=126000
divide bot sides by 15
a=8400

sub back
b+a=20000
b+8400=20000
minus 8400 both sides
b=11600




11,600 tickets sold before
8400 tickets sold after

How do I solve: 8 – (m - 3) = 7 – 3m​

Answers

Answer:

m=-2

Step-by-step explanation:

8-(m-3)=7-3m

8-1(m)-1(-3)=7-3m

8-m+3=7-3m

-m+3m+8+3=7-3m+3m

2m+8+3=7

2m+11=7

2m=-4

m=-2

Hope this helps!

Step-by-step explanation:

So, this is how you do it.

Let W be a point between points U and V on . If UV = 13, UW = 2y – 9, and WV = y – 5, solve for y.

Answers

Answer:

The value of y is 9.

Step-by-step explanation:

Given : W be a point between points U and V also,  UV = 13, UW = 2y – 9, and WV = y – 5

We have to solve for y.

Since,  W is a point between points U and V .

Then distance of point W from U and distance of point from V is equal to the distance of UV.

Then,   UW + WV = UV  

Substitute , the values, we get,

Then  2y – 9 +  y – 5 = 13

Solving for y , we get,

⇒ 3y - 14 = 13

⇒  3y = 13 + 14

⇒ 3y = 27

⇒  y = 9

Thus, the value of y is 9.

you would do 9/2
9/2=4.5
2*4.5=9

A cup of coffee at 181 degrees is poured into a mug and left in a room at 66 degrees. After 6 minutes, the coffee is 139 degrees. Assume that the differential equation describing Newton's Law of Cooling is (in this case) dT/dt=k(T-66).1) What is the temperature of the coffee after 16 minutes?
2) After how many minutes will the coffee be 100 degrees?

Answers

The temperature of the coffee after 16 minutes is 134 degrees and after 1.3 minutes the coffee be 100 degrees.

What is Differential equation?

A differential equation is an equation that contains one or more functions with its derivatives.

A cup of coffee at 181 degrees is poured into a mug and left in a room at 66 degrees.

After 6 minutes, the coffee is 139 degrees.

Assume that the differential equation describing Newton's Law of Cooling is (in this case) dT/dt=k(T-66).

T=∫k(t-66)dt

=k(t²/2-66)+c

When t=0 and T=181

181=k(0-66)+c

181=-66k+c

when t=6, T=139

139=k(6²/2-66)+c

139=-48k+c

-42=-18k

Divide both sides by 18

k=7/3

139=-48×7/3+c

c=139+112=251

T=7/3(t-66)+251

The temperature of the coffee after 16 minutes

T=7/3(16-66)+251

T=7/3(-50)+251

T=134 degrees

After how many minutes will the coffee be 100 degrees

100=7/3(t-66)+251

100=7/3t-7/3(66)+251

100=7/3t-154+251

100=7/3t+97

100-97=7/3t

3=7/3t

9/7=t

1.3=t

Hence, the temperature of the coffee after 16 minutes is 134 degrees and after 1.3 minutes the coffee be 100 degrees.

To learn more on Differentiation click:

brainly.com/question/24898810

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Answer:

Step-by-step explanation:

(dT)/(dt) =k(t-66)\nT=\int\ {k(t-66)} \, dt=K((t^2)/(2)  -66)+c\nwhen t=0,T=181\n181=K(0-66)+c\n181=-66k+c\nwhen t=6,T=139\n139=k((6^2)/(2) -66)+c\n139=-48k+c\n181-139=-66k+48k\n-42=-18k\n7=3k\nk=(7)/(3) \n139=-48*(7)/(3) +c\nc=139+112=251\nT=(7)/(3) (t-66)+251\nnow complete the question