Answer:
m=-2
Step-by-step explanation:
8-(m-3)=7-3m
8-1(m)-1(-3)=7-3m
8-m+3=7-3m
-m+3m+8+3=7-3m+3m
2m+8+3=7
2m+11=7
2m=-4
m=-2
Hope this helps!
Step-by-step explanation:
So, this is how you do it.
Answer:
The value of y is 9.
Step-by-step explanation:
Given : W be a point between points U and V also, UV = 13, UW = 2y – 9, and WV = y – 5
We have to solve for y.
Since, W is a point between points U and V .
Then distance of point W from U and distance of point from V is equal to the distance of UV.
Then, UW + WV = UV
Substitute , the values, we get,
Then 2y – 9 + y – 5 = 13
Solving for y , we get,
⇒ 3y - 14 = 13
⇒ 3y = 13 + 14
⇒ 3y = 27
⇒ y = 9
Thus, the value of y is 9.
2) After how many minutes will the coffee be 100 degrees?
The temperature of the coffee after 16 minutes is 134 degrees and after 1.3 minutes the coffee be 100 degrees.
A differential equation is an equation that contains one or more functions with its derivatives.
A cup of coffee at 181 degrees is poured into a mug and left in a room at 66 degrees.
After 6 minutes, the coffee is 139 degrees.
Assume that the differential equation describing Newton's Law of Cooling is (in this case) dT/dt=k(T-66).
T=∫k(t-66)dt
=k(t²/2-66)+c
When t=0 and T=181
181=k(0-66)+c
181=-66k+c
when t=6, T=139
139=k(6²/2-66)+c
139=-48k+c
-42=-18k
Divide both sides by 18
k=7/3
139=-48×7/3+c
c=139+112=251
T=7/3(t-66)+251
The temperature of the coffee after 16 minutes
T=7/3(16-66)+251
T=7/3(-50)+251
T=134 degrees
After how many minutes will the coffee be 100 degrees
100=7/3(t-66)+251
100=7/3t-7/3(66)+251
100=7/3t-154+251
100=7/3t+97
100-97=7/3t
3=7/3t
9/7=t
1.3=t
Hence, the temperature of the coffee after 16 minutes is 134 degrees and after 1.3 minutes the coffee be 100 degrees.
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Answer:
Step-by-step explanation: