The value of x in the equation a – bx = cx + d is = a - d / c + b
The value of x in the equation 5 – 6x = 8x + 17 is - 6 / 7
a - bx = cx + d
add bx to both sides of the equation
a - bx + bx = cx + bx + d
a = cx + bx + d
subtract d form both sides of the equation
a - d = cx + bx + d - d
a - d = cx + bx
using distributive law on the right side of the equation
a - d = x (c + b)
divide both sides by (c + b)
Therefore,
x = a - d / c + b
Let's use the same method to solve 5 – 6x = 8x + 17
5 – 6x = 8x + 17
add 6x to both sides
5 – 6x + 6x= 8x + 6x + 17
5 = 14x + 17
subtract 17 from both sides
5 - 17 = 14x + 17 - 17
-12 = 14x
divide both sides by 14
x = -12 / 14
x = - 6 / 7
learn more on equations here: brainly.com/question/7838122
Hmmm I don't think either is correct.
So he weighs 44 pounds, and needs to lose 7 pounds
44 - 7 = x
where x is the dog's new weight.
Answer:
Side-Side-Side [SSS]
Step-by-step explanation:
You know this since the little bars sticking outside of the triangle show that those 2 lines are congruent. Then you know of one line being the same for both, so you then know all of the sides. And since all of the side lengths are equal, this triangle is congruent by Side-Side-Side.
What is
21 times x = 7
Answer:
x = 1/3
Step-by-step explanation:
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other:
21x = 7
Divide 21 from both sides:
(21x)/21 = (7)/21
x = 7/21
x = 1/3
x = 1/3 is your answer.
~
Answer: is 3 unless you mean that the x=7 if you mean that then it would be 147
E=13,000 andE=1/50R(1650-R)
0.02R(1650-R)=13000
(0.02R)(1650)-0.02R²=13000
0.02R²-33R+13000=0
R2-1650R+650000=0
SOLVE W QUAD FORMULA
X
12.
600
X=
Answer:
Step-by-step explanation:
Since the figure above is a right angled triangle we can use trigonometric ratios to find x
To find x we use sine
sin ∅ = opposite / hypotenuse
From the question
The hypotenuse is 12
The opposite is x
Substitute the values into the above formula and solve for x
That's
We have the final answer as
Hope this helps you
B. 405
C. 1,215
The fifth term of a sequence whose first term is 5 and whose common ratio is 3 will be 405. Then the correct option is B.
A series of non-zero integers where every term after the first is obtained by increasing the one before it by a constant, non-zero value known as the scale factor.
Let a₁ be the first term and r be the common ratio.
Then the nth term of the geometric sequence is given as,
aₙ = a₁ · (r)ⁿ⁻¹
The first term is 5 and its common ratio is 3. Then the formula is given as,
aₙ = 5 · (3)ⁿ⁻¹
The fifth term of a sequence will be given as,
a₅ = 5 · (3)⁵⁻¹
a₅ = 5 · (3)⁴
a₅ = 5 · 81
a₅ = 405
The fifth term of a sequence whose first term is 5 and whose common ratio is 3 will be 405. Then the correct option is B.
More about the geometric sequence link is given below.
#SPJ2