A father is four times as old as his daughter. In 18 years he will be two times as old as she. How old is the daughter now?

Answers

Answer 1
Answer: Let's say x to the daughter's age, since the father's age is four times the daughter's age, his age will be 4x. 18 years later, the daughter's age will be x+18 and the father's will be 4x+18. And we know that 18 years later the father's age will be twice the daughter' so , 4x+18 = 2(x+18) and 4x+18=2x+36 then, 4x-2x=36-18,
2x=18 then divide both sides by 2, x = 9. The daughter's age was x, so she is 9 years old.

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What is the sum of the first five terms of a geometric series with a1 = 10 and r = 1/5? Express your answer as an improper fraction in lowest terms without using spaces.

Answers

Using the formula for the sum,
  Sn = a₀×(rⁿ -1)/(r -1)
you have
  S₅ = 10×((1/5)⁵ -1)/(1/5 -1)
  = 10×(-3124/3125)/(-4/5)
  = 10×781/625

  S₅ = 1562/125

_____
Or, you can add up the terms
  10 + 2 + 2/5 + 2/25 + 2/125 = (1250 +250 +50 +10 +2)/125
  = 1562/125

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

I hope its clear. Does this help??

What is the slope of the line that passes through 2,-1 and 2,-5

Answers

Answer:

Undefined.

Step-by-step explanation:

When using the formula y2-y1/x2-x1, the result comes out as -4/0. Any number over a 0 is undefined.

HELP! The average male Burns about 100 calories per mile and 140 calories per mile joggimg. using X to represent the miles walked and y to represent miles johged. Write a linear inequality modeling the number of miles a man should walk and jog in order to burn at least 500 calories

Answers

Answer:ididnt ask

Step-by-step explanation:

yes

Factorize 16x^2 + 16xy + 4y^2. A) (4x + 2y)^2 B) (4x - 2y)^2 C) 4(x + y)^2 D) 4(x - y)^2

Answers

Answer:

A

Step-by-step explanation:

given

16x² + 16xy + 4y²

an expression factorised as a perfect square has the form

(ax + by)²

= a²x² + 2abxy + b²y²

16x² + 16xy + 4y² ← is in this form

with a² = 16 , b² = 4

so a = √(16) = 4 and b = √(4) = 2

then 2ab = 2(4)(2) = 16

Thus

16x² + 16xy + 4y² = (4x + 2y)² ← in factorised form

 

Which values, when placed in the box, would result in a system of equations with no solution? Check all that apply.y = –2x + 4

6x + 3y =


A: –12

B: –4

C: 0

D: 4

E: 12

Answers

For this case we have the following system of equations:

Rewriting equation 1 we have:

Therefore, the equivalent system is:

The system will have no solution, if we write equation 2 as a linear combination of equation 1.

Therefore, since both lines have the same slope, they are parallel.

Parallel lines do not intersect when they have different cut points.

Therefore, there is no solution for:

-12, -4, 0, 4

The system has inifinites solutions for:

12

This is because the lines intersect at all points in the domain.

Answer:

The values, when placed in the box, would result in a system of equations with no solution are:

A: -12

B: -4

C: 0

D: 4

Answer:

Thus, option (a), (b) , (c) , (d) are correct.

The system will have no solution for all values except 12.

Step-by-step explanation:

 Given a system of equation y = –2x + 4  and 6x + 3y = ?

We have to check for which value the '?'  would result in a system of equations with no solution.

Consider a system of equation  a_1x+b_1y+c_1=0 \n\na_2x+b_2y+c_2=0

For the system to have no solution the condition is,

(a_1)/(a_2)=(b_1)/(b_2)\neq (c_1)/(c_2)

For the given system of equation ,

Let unknown quantity be v.

y = –2x + 4   ⇒ 2x +y - 4 = 0  

and 6x + 3y = v ⇒  6x + 3y - v =0

On comparing, we get,

a_1=2 , b_1=1,c_1=-4\n\n\a_2=6,b_2=3,c_3=-v

Substitute the values in condition for no solution , we get ,

(2)/(6)=(1)/(3)\neq (-4)/(-v)

Consider second and third ratio, we get,

(1)/(3)\neq (-4)/(-v)

Solve for v , we get,

(1)/(3)\neq (-4)/(-v) \n\n \Rightarrow v \neq 12  

Thus, for all values v except v = 12

The system will have no solution

at v = 12 the system will have infinite many solution.

Thus, option (a), (b) , (c) , (d) are correct.