in a class of 28 sixth graders all but one of the students are 12 years old. witch two data measurements are the same for the students ages/ what are those measurements? please help

Answers

Answer 1
Answer: out of 28 kids there is one that isnt 12
so 27 kids are 12 years old
1 isnt
concluding that, that 6th grade might be 11
so 1 out of 28
1:28



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What is the fraction of 3\4 of 28

Answers

If you are trying to find 3/4 of 28, multiply 3/4 (or 0.75( by 28), which equals 21.

3/4 • 28 = 21

Adriana's soccer ball is covered with a pattern of pentagons and hexagons in the ratio of 3 to 5. If there are 12 pentagons, how many hexagons are in the pattern?

Answers

Hello There!

This is a multiple step problem, to solve this you have to multiply and divide. 

Steps
1. Divide 12 by 3

2. You should get 4, to check you're answer do 3*4 which equals 12

3. To find how many hexagons there are, you have to do 4*5 which equals 20

So, on Adriana's soccer ball if there are 12 pentagons, there should be 20 hexagons.

Hope This Helps :)


A beach ball has a radius of 9 inches. find the volume of the beachball, in cubic inches and round the answer to the nearest whole number

Answers

V=4/3pi(r^3)
V=4/3pi(9^3)
V=3,054 inches^3

Think this is right
3053.63 which would be rounded to 3054.

The avocado own a 1/4 acre orchard. Two fifths of the orchard  is planted in orange trees. What fraction of an acre in planted in orange trees

Answers

Two\ fifths\ of\ the\ orchard= (2)/(5) \cdot (1)/(4)\ acre= (1)/(10) \ acre\n\nAns.\ 0.1\ acre\ in\ orange\ trees.
(2/5) x (1/4) = 2/20 = 1/10 of an acre

9-2 in fractions simplest form answer

Answers

8/1 =9-2

4 1/2=9/2

Im not sure what u meant but u prob meant the 2nd one

9/2 in simplist form is a mixed number 4 1/2

Solve the formula for the perimeter of a rectangle with width w and length l,for the length P=2w+2l solve for l

Answers

Answer:

l=(P)/(2)-w

Step-by-step explanation:

we know that

The formula for the perimeter of a rectangle is equal to

P=2(w+l)

where

l is the length

w is the width

Solve for l

That means ----> Isolate the variable l

Divide by 2 both sides

(P)/(2)=(2(w+l))/(2)

Simplify right side

(P)/(2)=w+l

Subtract w both sides

(P)/(2)-w=w+l-w

Simplify right side

(P)/(2)-w=l

Rewrite

l=(P)/(2)-w

Answer:Solve P = 2l + 2w for w.

The first step is to isolate the variable term, 2w.

Step-by-step explanation: