How many hydrogen atoms are represented in the formula (CH3)2CH2?

Answers

Answer 1

Answer: 7 ..... i think because in CH3 there would be 3 H atoms while in 2CH2 there would be four

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What gives the color and shape characteristics to flames in a fire?

Answers

Answer:

Different ions of different elements (usually metals) make a flame burn with a characteristic color when introduced into the reaction zone; the different colors are caused by the different quantized energy levels of the electrons in the different atoms.

Write a complete reaction of succinic acid and acetic anhydride

Answers

answer is below...................

Describe the capillary action in acetone compared to water

Answers

Capillary action is defined as the ability of a liquid to go up a narrow space without the help or opposition of external forces. One of the most important factors affecting capillary action is the intermolecular forces within a substance. The higher the IMF, the greater the capillary action. The H-bonding in water gives it greater IMF than acetone, so water has greater capillary action.

Liquid going up a thin space without the assistance off an opposite or opposing force

29 Which term identifies a type of nuclear reaction?(1) fermentation (3) reduction
(2) deposition (4) fission

Answers

Answer:The correct answer is option (4).

Explanation:

Nuclear reaction :These the chemical reaction in which change in identity of a nucleus of an atom takes place.It is of two types:

Fusion is a process which involves the conversion of two small nuclei to form a heavy nuclei along with release of energy.
Fission is a process which involves the conversion of a heavier nuclei into two or more small and stable nuclei along with the release of energy.

From the given options the option identifying the nuclear reaction is fission.Hence. the correct answer is option 4.

4) fission is a nuclear reaction where the nucleus of a reactant breaks apart

1 point14. Which factor is not needed hen calculating the velocity of a satellite
orbiting a planet?
the mass of the satellite
the orbital radius of the satellite
the mass of the planet
the universal gravitational constant
Pls help I will give extra points

Answers

The mass of the satellite is not required when calculating the velocity of a satellite orbiting a planet.

Given that the centripetal force on the satellite is;

F = mv^2/r

Where;

F = centripetal force that keeps the satellite in its orbit

m = mass of the satellite

r = radius of the satellite

Since the force of gravity and the centripetal force both act on the satellite and they are exactly balanced;

F = GMm/r^2

Where;

G = gravitational constant

M = mass of the planet

m = mass of the satellite

r = radius of the satellite

Hence;

F = GMm/r^2 = mv^2/r

GMm/r^2 = mv^2/r

v = √GM/r

Thus, the mass of the satellite is not required when calculating the velocity of a satellite orbiting a planet.

Learn more: brainly.com/question/21454806

Answer:

i. the mass of the satellite will not be required in this calculation

Explanation:

When a satellite is orbiting a planet, it experiences two forces. The centripetal force and the gravitational force that the planet exerts on the satellite. In order for the satellite to keep in orbit, the centripetal force and the gravitational force must be equal.

The expression for the centripetal force is:

F_c = (m_s)v² / R

where

m_s is the mass of the satellite

R is the radius of the satellite's orbit

v is the velocity that the satellite travels with around the planet

The expression for the Gravitational force is:

F_g = (G M_p m_s) / R²

where

G is the universal gravitational constant

M_p is the mass of the planet

m_s is the mass of the satellite

R is the radius of the satellite's orbit

Thus, equating the two forces together, we get:

(G M_p m_s) / R² = (m_s)v² / R

We can cancel out m_s since it is a common factor on both sides.

Thus,

(G M_p) / R² = v² / R ⇒ M_p = v²R / G

Therefore, the mass of the satellite is not required to calculate the mass of the planet.

Explanation:

Hope this helps:)

The gases listed are at standard temperature and pressure: · 1 mol of CO2 gas · 1 mol of N2 gas · 2 mol of O2 gas Which statement is correct? The volume of 1 mol of CO2 is greater than that of 2 mol of O2 . The volume of 1 mol of CO2 is greater than that of 1 mol of N2 . The volumes of 2 mol of O2 and 1 mol of N2 gases are the same. **The volumes of 1 mol of CO2 and 1 mol of N2 gases are the same.**

Answers

Answer : The volume of 1 mole of $CO_(2)$ and $N_(2)$ gases are the same.

Solution: Given,

Moles of $CO_(2)$ = 1 mole

Moles of $N_(2)$ = 1 mole

Moles of $O_(2)$ = 2 mole

Formula used for ideal gas is :

P V = n R T

According to the question, the gases are at standard temperature and pressure. So, the volume of gases only depends on the number of moles. This means that the higher the number of moles, higher will be the volume of gas.

The moles of $O_(2)$ are more than the moles of $CO_(2)$ and $N_(2)$ . So, the volume of $O_(2)$ will be more.

And the moles of $CO_(2)$ and $N_(2)$ are equal. Therefore, their volumes are also equal.

Therefore, the best option is the volume of 1 mole of $CO_(2)$ and $N_(2)$ gases are the same.

The right answer for the question that is being asked and shown above is that: "The volumes of 1 mol of CO2 and 1 mol of N2 gases are the same." The statement that is correct as far as the gases listed are at standard temperature and pressure is concerned is that the volumes of 1 mol of CO2 and 1 mol of N2 gases are the same

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