The movie theater has 250 seats 225 seats were sold for the carriage showing what percent of seats are empty?

Answers

Answer 1
Answer: Well 25 seats are available so 25/250 equals 0.1 or
10%

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Find the coordinates for the midpoint of the segment with endpoints given. (5, 6) and (8, 2)

Answers

we first introduce midpoint formula
X1+X2 over 2;Y1+Y2 over 2
5+8 over 2 ; 6+2 over 2
x=13 over 2 ; Y=4
therefore midpoint=(13/4;4)

The endpoints of AB are A(9,4) and B(5,-4). The endpoints of its image after a dilation ar A(6,3) and B(3,-3). a. explain how to find te scale factor. b. locate the center of dilation. show your work

Answers

Look at the picture for the answer.

Final answer:

The scale factor of the dilation is calculated by dividing the length of the line after dilation by the length of the initial line. The length of a line is calculated using the distance formula. The center of dilation is the point from which the shape scales, but we can't determine its location without more information.

Explanation:

To find the scale factor of a dilation in a two-dimensional plane, we divide the length of the line after dilation by the length of the initial line. The length of a line can be calculated using the distance formula which is √[(x₂ - x₁)² + (y₂ - y₁)²].

For AB, the distance will be √[(5 - 9)² + (-4 - 4)²] = √[(-4)² + (-8)²] which equals √80. For A'B', the distance will be √(3 - 6)² + (-3 - 3)² = √[(-3)² + (-6)²] which equals √45. The scale factor (k) of the dilation is the ratio of these distances, so k = √45 / √80 which simplifies to √(9/16) or 3/4.

Unfortunately, without more information, such as a fixed point in the original shape, we can't determine the exact location of the center of dilation. But, conceptually, it's the point that the shape is scaling towards or away from during the dilation.

Learn more about Dilation in Mathematics here:

brainly.com/question/27593412

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Please help i will mark brainliest

Answers

Answer:

The coordinates of mage of L(5, 10) will be: (11, 3)

So, the 4th (last) option is correct.

Step-by-step explanation:

As we know that Translation means how much a point is moved to the left/right and up/down.

  • Given the translation maps the point J(1, 4) onto K(7, -3).

As the x-coordinate of the image point K(7, -3) is 7 which is 6 units right to the original point J(1, 4).

Also, the y-coordinate of the image point K(7, -3) is -3 which is 7 units down to the original point J(1, 4)

so it means the translation basically implies that

(x, y) → (x + 6, y - 7)

Hence, the coordinate of the image of L(5, 10) can also be determined by

using the same rule.

(x, y) → (5 + 6, 10 - 7) = (11, 3)

Therefore,  the coordinates of mage of L(5, 10) will be: (11, 3)

So, the 4th (last) option is correct.

Find the value of the following:|-15|.​

Answers

Answer:

The answer is 15 because that absolute value for anything is 15. No matter what number

Step-by-step explanation:

Please Help me Check the image below!!!!!

Answers

Answer:

First question:

The graph of  y=(3-2x)/(2-3x) has a vertical asymptote at x =  (2)/(3)and a horizontal asymptote at y =  (2)/(3)

Second question:

The graph of equation y=(1-3x)/(2+x) has a horizontal asymptote at y = -3 ⇒ C

Step-by-step explanation:

The vertical asymptotes will occur at the values of x for which make the  denominator is equal to zero

The horizontal asymptotes will occur if:

  • Both polynomials are the same degree, divide the coefficients of the highest degree terms
  • The polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote

First question:

y=(3-2x)/(2-3x)

- To find the vertical asymptote equate the denominator by 0

   to find the value of x

∵ The denominator is 2 - 3x

∴ 2 - 3x = 0

- Add 3x to both sides

∴ 2 = 3x

- Divide both sides by 3

(2)/(3) = x

The graph has a vertical asymptote at x =  (2)/(3)

To find the horizontal asymptote look at the highest degree of x in both numerator and denominator

∵ The denominator and the numerator has the same degree of x

- Divide the coefficient of x of the numerator and denominator

∵ The coefficient of x in the numerator is -2

∵ The coefficient of x in the denominator is -3

∵ -2 ÷ -3 = (2)/(3)

The graph has a horizontal asymptote at y =  (2)/(3)

The graph of  y=(3-2x)/(2-3x) has a vertical asymptote at x =  (2)/(3) and a horizontal asymptote at y =  (2)/(3)

Second question:

The graph has a horizontal asymptote at y = -3

means the numerator and the denominator has same highest degree and the coefficient of the highest degree in the numerator divided by the coefficient of the highest degree in the denominator equal to -3

  • In all answers the numerator and the denominator have the same highest degree
  • Lets look for the coefficients of x up and down to find which one gives quotient of -3

∵ In answer A the quotient is 1 because x up and down have

  coefficient 1

∵ In answer B the quotient is -(1)/(3) because the coefficient of x

   up is 1 and down is -3

∵ In answer D the quotient is -1 because the coefficient of x

   up is 3 and down is -3

∵ In answer C the quotient is -3 because the coefficient of x up

   is -3 and down is 1

The graph of equation y=(1-3x)/(2+x) has a horizontal asymptote at y = -3

. Use the process outlined in the lesson to approximate the number 3√10. Use the approximation √10 ≈3162 277 7.. Find a sequence of five intervals that contain 3√10 whose endpoints get successively closer to 3√10. Write your
iintervals in the form 3^???? < 3^√10 < 3^s for rational numbers ????and s.

Answers

Answer:

sequence of five intervals

(1) 3³  < 3^(√(10) )   < 3^(4)

(2) 3^(3.1)  < 3^(√(10) )   < 3^(3.2)

(3) 3^(3.16) < 3^(√(10) )   < 3^(3.17)

(4) 3^(3.162) < 3^(√(10) )   < 3^(3.163)

(5) 3^(3.1622)  < 3^(√(10) )   < 3^(3.1623)

Step-by-step explanation:

as per question given data      

√10 ≈ 3.162 277 7    

to find out      

sequence of five intervals

solution      

as we have given that √10 value that is here

√10 ≈ 3.162 277 7           ........................1

so  

when we find 3^(√(10) )           ................2

put here √10 value in equation number  2  

we get  3^(√(10) )   that is  32.27    

so    

sequence of five intervals

(1) 3³  < 3^(√(10) )   < 3^(4)

(2) 3^(3.1)  < 3^(√(10) )   < 3^(3.2)

(3) 3^(3.16) < 3^(√(10) )   < 3^(3.17)

(4) 3^(3.162) < 3^(√(10) )   < 3^(3.163)

(5) 3^(3.1622)  < 3^(√(10) )   < 3^(3.1623)