4x^2-28x+49=5 solve the quadratic by completing the square

Answers

Answer 1
Answer: 4x^2-28x+49=5 \n \n4x^2-28x+49-5=0\n \n4x^2-28x+44=0\n \n \Delta = b^(2)-4ac =(-28)^(2)-4*4*44=784 - 704 = 80 \n \nx_(1)=(-b-√(\Delta ))/(2a) =(28- √(80))/(2*4)=(-28-√(16*5))/(8)= (-28-4√( 5))/(8)=\n \n=(\not4^1(-7- √( 5)))/(\not8^2)=( -7- √( 5) )/(2)=

x_(2)=(-b+√(\Delta ))/(2a) =(28+√(80))/(2*4)=(-28+√(16*5))/(8)= (-28+4√( 5))/(8)=\n \n=(\not4^1(-7+ √( 5)))/(\not8^2)=( -7+ √( 5) )/(2) \n \nAnswer : x=( -7- √( 5) )/(2) \ \ or \ \ x =( -7+ √( 5) )/(2)



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Help please odds only geometry

Answers

1)
log 98 = log( 7 * 14 ) = log 7+ log 14= h  +  j ;

2) 
log 175 = log ( 5^2 * 7 ) = log 5 ^ 2 + log 7 = 2 * log 5 + log 7 = 2i + h ;

3)
log 2 = log ( 14 / 7 ) = log 14 - log 7 = j  -  h ;

4)
log 245 = log ( 7^2 * 5 ) = log 7 ^2 + log 5 = 2 * log 7 + log 5 = 2h + i ;
\log98=\log(7\cdot14)=\log 7+\log14=h+j\n\n\log175=\log(5^2\cdot7)=\log5^2+\log7=2\log5+h=2i+h\n\n\log2=\log(14)/(7)=\log14-\log7=j-h\n\n\log245=\log(5\cdot7^2)=\log5+\log7^2=i+2\log7=i+2h

16/8 into a mixed number

Answers

ok well the answer will be 2 because 8+8=16 and 8 can go into 16 2 times.
the answer is 
2/1 
because 8 times 2 is 16 and if  you divide 16 by 8 u will get 2 and 8 divided by 8 is 1

Write log8 3 as a logarithm of base 5.1) (log3)5/(log8)5
2) (log5)3/(log5)8
3) (log8)5/(log3)5
4) (log5)8/(log5)3 ...?

Answers

The answer is 2) (log5)3/(log5)8

We will use the change-of-base formula: log_a(x)= (log_b(x))/(log_b(a))

So, if we want to write log8 3 as a logarithm of base 5,  in these example a = 8, x = 3, b = 5:
log_8(3)= (log_5(3))/(log_5(8))

What is the answer to this?

Answers

I got / 33/4. If I’m wrong sorry

If E is on the interior of ∠ABD, m∠ABE = (2x - 5)°, m∠EBD = (x + 1)°, and m∠ABD = 50°, find the value of x.

Answers

   
\displaystyle \n m\ \textless \ ABE + m\ \textless \ EBD = m\ \textless \ ABD \n \n (2x - 5)^o + (x + 1)^o = 50^o \n \n 2x-5+x+1=50 \n \n 3x - 4 = 50 \n \n 3x = 50+4 \n \n 3x = 54 \n \n x = (54)/(3) = \boxed{18^o}



1.What is the simplified form of each expression?7x^–8 × 6x^3

a. 42/x^5
b. 1/42x^5
c. 42x^11
d. 13x^–5

(–2x8) · 3y9 · 2x4

a. 3x^12y^9
b. –12x^72y^9
c. –12xy^21
d. –12x^y^9

2. Find the simplified form of the expression. Give your answer in scientific notation.

(8 x 10^7) (7 x 10^4)

a. 1.5 × 10^12
b. 5.6 × 10^12
c. 1.5 x 10^29
d. 5.6 x 10^29


(7 × 10^–4)(9 × 10^–10)

a. 6.3 × 10^–13
b. 63 × 10^–13
c. 6.3 × 10^–15
d. 6.3 × 10^–16

Answers

Answer with explanation:

Ques 1)

A)

         We are given a expression as:

    7x^(-8)* 6x^3

It could also be written as:

  (7* 6)* x^(-8)* x^3\n\n\n=42* x^(-8+3)\n\n\n=42x^(-5)\n\n\n=(42)/(x^5)

  Option: a is the answer.

B)

     (-2x^8)* 3y^9* 2x^4

which is solved as follows:

(-2* 3* 2)* x^8* y^9* x^4\n\n\n=-12x^(8+4)* y^9\n\n\n=-12x^(12)y^9

Ques 2)

A)

The expression is:

         (8* 10^7)(7* 10^4)

It is solved as:

  =(8* 7)* 10^7* 10^4\n\n\n=56* 10^(7+4)\n\n\n=56* 10^(11)\n\n\n=5.6* 10^(12)

                 Option: b is the answer.

B)

           (7* 10^(-4))(9* 10^(-10))

On simplifying:

     =7* 9* 10^(-4)* 10^(-10)\n\n\n=63* 10^(-4-10)\n\n\n=63* 10^(-14)\n\n\n=6.3* 10^(-14+1)\n\n\n=6.3* 10^(-13)

                   Option: a is the answer.