The molar mass of calcium sulfate (CaSO₄) is approximately 136.14 grams per mole (g/mol).
To calculate the molar mass of CaSO₄ (calcium sulfate), you need to sum up the atomic masses of all the individual atoms in the chemical formula.
The atomic masses (molar masses) of the elements are as follows:
Calcium (Ca) has a molar mass of approximately 40.08 g/mol.
Sulfur (S) has a molar mass of approximately 32.06 g/mol.
Oxygen (O) has a molar mass of approximately 16.00 g/mol.
Now, let's calculate the molar mass of CaSO₄:
Molar mass of CaSO₄ = (Molar mass of Ca) + (Molar mass of S) + 4 × (Molar mass of O)
Molar mass of CaSO₄ = 40.08 g/mol + 32.06 g/mol + 4 × 16.00 g/mol
Molar mass of CaSO₄ = 40.08 g/mol + 32.06 g/mol + 64.00 g/mol
Molar mass of CaSO₄ = 136.14 g/mol
So, the molar mass of calcium sulfate (CaSO₄) is approximately 136.14 grams per mole (g/mol).
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Which is larger a zinc atom or a zinc ion? explain
Answer:
The correct answer is because they work at different pH levels.
Explanation:
The pH varies because the different enzymes secreted in the stomach work at different pH levels. Gastric secretion is the most important stage of digestion since when the food comes into contact with a low pH and the enzymes present, they dissociate it and denature the proteins present.
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(2) HI
(3) LiH
(4) NH3
An Arrhenius acid is a proton donor, hence among the following, HI is an Arrhenius acid in aqueous solution.
Acids are defined as substances which on dissociation yield H+ ions , and these substances are sour in taste. Compounds such as HCl, H₂SO₄ and HNO₃ are acids as they yield H+ ions on dissociation.
According to the number of H+ ions which are generated on dissociation acids are classified as mono-protic , di-protic ,tri-protic and polyprotic acids depending on the number of protons which are liberated on dissociation.
Acids are widely used in industries for production of fertilizers, detergents batteries and dyes.They are used in chemical industries for production of chemical compounds like salts which are produced by neutralization reactions.
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A: The rate of formation of R is one-half the rate of the disappearance of Z.
B: The rate of disappearance of Z is one-fourth of the rate of disappearance of X.
C: The rate of formation of R is double the rate of formation of S.
D: The rate of formation of S is double the rate of disappearance of X.
B: The rate of disappearance of Z is one-fourth of the rate of disappearance of X
Because as x -> 0, 4->0
z-> 0, 1->0
B) Weak electrolytes dissolve and partially dissociate in water providing charged ions to conduct electricity.
C) Weak electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.
D) Weak electrolytes dissolve and does not dissociate in water providing no charged ions to conduct electricity.
Answer: B) Weak electrolytes dissolve and partially dissociate in water providing charged ions to conduct electricity.
Explanation: Weak electrolytes are those substances which do not dissociate completely when dissolved in water. They dissociate but then associate back and thus their dissociation is shown by an equilibrium sign. Example:
The charged species formed helps in the conduction of electricity.
Strong electrolytes are those substances which dissociate completely when dissolved in water. Their dissociation is shown by a forward arrow. Example:
The charged species formed helps in the conduction of electricity.