Which of the ordered pairs satisfy the equation below check all that apply y=-9x
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Solve for n: 6n+12=12
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Answer:
Angle E has
Step-by-step explanation:
we know that
Observing the figure, according to the protractor
Angle B has
Angle C has
Angle D has
Angle E has
Angle F has
a. 58.88
b. 5.89
c. 1,113.04
d. 11.13
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Option C:
f(x) = 5x + 7 is the function of the input-output table.
Solution:
Option A: f(x) = 6x + 9
Input x = 1 in the above equation.
f(1) = 6(1) + 9
= 6 + 9
f(1) = 15
But the output is 12 in the table.
So, it is not the function of the table.
Option B: f(x) = 7x + 5
Input x = 1 in the above equation.
f(1) = 7(1) + 5
f(1) = 12
Input x = 5 in the above equation.
f(5) = 7(5) + 5
f(5) = 40
But the output is 32 in the table.
So, it is not the function of the table.
Option C: f(x) = 5x + 7
Input x = 1 in the above equation.
f(1) = 5(1) + 7
f(1) = 12
Input x = 5 in the above equation.
f(5) = 5(5) + 7
f(5) = 32
Input x = 10 in the above equation.
f(10) = 5(10) + 7
f(10) = 57
Input x = 5 in the above equation.
f(15) = 5(15) + 7
f(15) = 82
All outputs are correct for the given input.
Hence it is the function of the table.
Option D: f(x) = 12x + 1
Input x = 1 in the above equation.
f(1) = 12(1) + 1
f(1) = 12
Input x = 5 in the above equation.
f(5) = 12(5) + 1
f(5) = 61
But the output is 32 in the table.
So, it is not the function of the table.
Hence Option C is the correct answer.
f(x) = 5x + 7 is the function of the input-output table.
26 + (–3) ∙ (–8)
a. –184
b. –2
c. 2
d. 50
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Answer:
the probability is 0%
Step-by-step explanation:
is there options like
A
B
C
options
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Answer:
The additive inverse of given expression is .
Step-by-step explanation:
The given polynomial is
Let a be any number and b is its additive inverse, then
The value of b is equal to -a. It means the additive inverse of a is -a.
The additive inverse of given expression is
Therefore the additive inverse of given expression is .
-1(9xy² + 6x²y - 5x³) ⇒ (-1)(9xy²) + (-1)(6x²y) + (-1)(-5x³)
-9xy² - 6x²y + 5x³ is the additive inverse of the given polynomial.