To find the planet's radius in terms of the radius Rg of Earth, use the equation g = GM/R^2 and substitute 2g for g. Solve for R to get R = sqrt(1/(2gMg)) * Rg.
To find the planet's radius in terms of the radius Rg of Earth, we need to understand the relationship between the gravitational field and the mass and radius of a planet. The magnitude of the gravitational field on the surface of a planet is given by g = GM/R2, where G is the gravitational constant, M is the mass of the planet, and R is its radius. For the planet in question, we are told that the magnitude of the gravitational field is 2g and its mass is half the mass of Earth. Since the gravitational field is 2g, we can substitute g with 2g in the equation and solve for R in terms of Rg:
2g = GM/R2 → 2gR2 = GM → 2gR2 = (GMg)/(2Rg) → R2/Rg = 1/(2gMg) → R = sqrt(1/(2gMg)) * Rg
#SPJ12
To find the radius of a planet with a gravitational field twice that of Earth's and half the mass, the radius is calculated to be half of Earth's radius.
The magnitude of the gravitational field strength g on a planet is given by the equation g = G(M/R^2), where G is the universal gravitation constant, M is the planet's mass, and R is the planet's radius. Given that the gravitational field on the surface of the particular planet is 2g where g is Earth's gravitational field, and the planet's mass is half of Earth's mass, we can derive the planet's radius in terms of Earth's radius Rg. Setting up the proportion (G(1/2M_Earth)/(R^2)) / (G(M_Earth)/(Rg^2)) = 2, and simplifying, we find that R^2 = (1/4)Rg^2. Taking the square root of both sides gives us the final relation R = (1/2)Rg.
#SPJ3
b) A toaster
c) A battery-operated remote control car
d) A blender
By definition we have that the density is given by:
Where,
M: mass of the sample
V: volume occupied by the sample
Therefore, substituting values in the given equation we have:
Answer:
the density of a sample of gas with a mass of 30 g and a volume of 7500 cm3 is:
The density of the sample of gas is or .
Further Explanation:
Density of any kind of matter is defined as the total mass of that substance present in the volume occupied by it in the region of space.
Example (1) : If we consider equal amounts of tungsten and iron, then tungsten is heavier than iron because tungsten occupies lesser volume or lesser empty spaces inside it for a particular mass as compared to iron. Therefore, tungsten has density higher than that of iron.
Example (2): If we take 2 cubes of similar size (same volume) of tungsten and gold then the cube of gold will be heavier because its density is more than that of tungsten.
Given:
The mass of the sampleof the gas is .
The volume of the sample of the gas is .
Concept:
The density of the substance is defined as the ratio of the mass and volume.
......(1)
Here, is the density of the sample ofthe gas, is the mass of the sample of the gas and is the volume occupied by the gas.
Substitute the value of and in equation (1).
Thus, the density of the sample of gas is or .
Learn More:
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2. Which of the following is not a component of a lever brainly.com/question/1073452
3. A 30kg block being pulled on a carpeted floor brainly.com/question/7031524
Answer Details:
Grade: middle school
Subject: Physics
Chapter: Matter
Keywords:
Density, sample of gas, 30g gas, volume, 7500 cm3, 7500 cm^3, mass, matter, volume occupied, sample, ratio,grams per centimeter cube
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