In a mirror, the light ray undergoes reflection, in a glass block, the light ray undergoes refraction. For a prism, a light ray undergoes refraction and dispersion and in a glass box with a smooth surface, it may experience both reflection and refraction.
These processes of reflection, refraction, and dispersion may take place when the ray of light from the ray box is aimed at each of the objects:
Mirror: when a light beam strikes a mirror, it is reflected and reflects at an angle that is equal to the angle of incidence. According to the law of reflection, the angle of reflection and incidence are the same.
Glass Block: when a light beam penetrates a glass block at an angle, it changes direction as a result of the difference in light speed between the different media (glass and air). Refraction is the name given to this phenomenon. If the light in the glass slows down, the ray bends toward the normal, and if it speeds up, it bends away from the normal. The incidence angle and the glass's refractive index both affect how much bending occurs.
Prism: when a light beam enters a prism, it undergoes refraction as it transitions from air to the denser prism material. The rise in refractive index causes the ray to bend in the direction of the prism's base. Dispersion, or the separation of light into its individual colors (rainbow), is another effect of the prism. This occurs as a result of the various wavelengths of light diffracting differently as they pass through the prism. The stunning array of colors that occurs when light passes through a glass prism is caused by this phenomenon.
Hence, in a mirror, the light ray undergoes reflection, in a glass block the light ray undergoes refraction. For a prism, a light ray undergoes refraction and dispersion and in a glass box with a smooth surface, it may experience both reflection and refraction.
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Light from the stars is visible light and travels in longitudinal waves. Longitudinal waves require a medium to travel; therefore, light is reflected off particles of matter in space to be seen on the earth.
B.
Light from the stars is visible light and travels in electromagnetic waves. Electromagnetic waves require a medium to travel; therefore, light is reflected off particles of matter in space to be seen on the earth.
C.
Light from the stars is visible light and travels in electromagnetic waves. Electromagnetic waves do not require a medium to travel; therefore, light travels through the vacuum of space to be seen on the earth.
D.
Light from the stars is visible light and travels as surface to surface waves. Surface waves require a medium to travel; therefore, light travels from the surface of the star to the surface of the earth.
C.?
Answer:
A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.
Explanation:
We have equation of motion, , where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.
In this case we have final velocity = 10 m/s, initial velocity = 0 m/s, and acceleration = 9.8 .
Substituting
A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.
When an object, starting from rest, achieves an instantaneous speed of 10 m/s while freely falling under gravity, it will have fallen approximately 5.10 meters.
Using the physics concept of motion under gravity, where the first equation of motion can apply (v = u + gt), your question involves finding the displacement of a freely falling object starting from rest until it reaches a speed of 10 m/s.
In this case, initial velocity (u) is zero because the object was at rest, the final velocity (v) is 10 m/s, and g is the acceleration due to gravity which is approximately 9.81 m/s².
We could rearrange the equation to find time: t = v/g = 10 / 9.81 ≈ 1.02 s. Then, we employ the second equation of motion to find the distance fallen, s = ut + 0.5gt². Since u=0, the formula simplifies to s = 0.5gt². Substituting g = 9.81 m/s² and t = 1.02 s into the equation yields s = 0.5 * 9.81 * (1.02)² ≈ 5.10 m.
Therefore, a freely falling object will have fallen approximately 5.10 meters when its instantaneous speed is 10 m/s.
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