Why can't we change the subscripts in balancing chemical equations?
Answer : The new pressure of the gas will be, 468.66 atm
Explanation :
Boyle's Law : This law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
(At constant temperature and number of moles)
or,
where,
= initial pressure of the gas = 74 atm
= final pressure of the gas = ?
= initial volume of the gas = 190 ml
= final volume of the gas = 30 ml
Now we put all the given values in the above formula, we get the final or new pressure of the gas.
Therefore, the new pressure of the gas will be, 468.66 atm
Answer: The new pressure of the gas is 467 atm.
Explanation:
To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.
The equation given by this law is:
where,
are initial pressure and volume.
are final pressure and volume.
We are given:
Putting values in above equation, we get:
Hence, the new pressure of the gas is 467 atm.
c. turning lithium into fluorine.
b. losing or gaining protons.
d. losing or gaining electrons.
Answer:
Helium will be inert. Lithium is the most reactive element, followed by chlorine.
Explanation:
The elements tend to resemble the closest noble gases in terms of their electronic configuration of the last layer, that is, having eight electrons in the last layer to be stable. Then, the reactivity of an element measures the tendency to combine with others to generate the mentioned stability.
Within a period, the groups located on the left of the periodic table are more reactive than groups on the right. This is because it is easier to lose the electron of the last layer possessed by the elements located on the left than more than one electron in the rest of the elements. When we reach a certain group the trend is reversed since it will be easier to gain the missing electrons to resemble the nearest noble gas. Therefore, in a period the reactivity of metals increases the further to the left in the period (less electrons to remove). The reactivity of nonmetals increases as the period progresses since it is the case in which it is easier to acquire electrons to acquire stability, and increases to advance in a period since the less electrons they need to acquire, the more reactants they are.
Within a group, as we descend into it, the electrons of the last layer are farther from the nucleus and, therefore, it will be easier to remove them. In the case of nonmetals, it will be more difficult to take electrons. Then the reactivity of the metals increases when advancing in a group (greater tendency to lose electrons) and the reactivity of the nonmetals increases the higher in the group (greater tendency to take electrons).
Finally, you have noble or inert gases. Its inert name is due to the lack of reactivity with other elements. This is due to its electronic configuration, because its outermost layer or valence layer is always complete, without the need to share, transfer or receive electrons forming bonds. That is, its outer layer is so stable that the element tends not to react with others except in very specific cases.
Taking into account everything mentioned above, it is possible to say that helium is a noble gas, so it will be inert. Lithium is the most reactive element, followed by chlorine.
150 J
B.
270 J
C.
1350 J
D.
2250 J
The formula that can be applied in this problem is W = Fd where W is work, F is the force and d is distance. You have 450N and 3m, all you have to do is to multiply it.
W = Fd
W = (450N) (3m)
W = 1350J
The answer is letter C.
The final volume of the gas is approximately 3.24 mL when the pressure has increased from 5 mmHg to 589 mmHg.
To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas. The formula for the combined gas law is:
P1V1/T1 = P2V2/T2
where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final pressure, volume, and temperature of the gas.
In this problem, we are given the initial volume (V1 = 381 mL) and pressure (P1 = 5 mmHg), and we want to find the final volume (V2) when the pressure has increased to 589 mmHg. We can assume that the temperature remains constant.
We can start by rearranging the combined gas law to solve for V2:
V2 = (P1V1/T1) x (T2/P2)
Since the temperature is constant, we can simplify the formula to:
V2 = (P1V1)/P2
Plugging in the values we know, we get:
V2 = (5 mmHg x 381 mL)/589 mmHg
Simplifying, we get:
V2 = 3.24 mL
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