Speed of the motor cycle is given as
distance that he moved off from the ramp is given as
now we know that
now we can use this to find the height
so its height will be 75 cm from ground
The height of the ramp is approximately 0.748m.
To find the height of the ramp, we can use the equations of motion. Since the motorcycle leaves the ramp horizontally, the horizontal distance traveled is equal to the initial horizontal velocity multiplied by the time of flight.
Using the equation x = vt, where x is the horizontal distance traveled, v is the initial horizontal velocity, and t is the time of flight, we can solve for t.
For this problem, the horizontal distance is 40.0m and the initial horizontal velocity is 103m/s. Substituting these values into the equation, we get t = x/v = 40.0m / 103m/s = 0.388s.
Next, to find the height of the ramp, we can use the equation h = (1/2)gt^2, where h is the height of the ramp and g is the acceleration due to gravity (approximately 9.8m/s^2). Substituting the value of t we found into the equation, we get h = (1/2)(9.8m/s^2)(0.388s)^2 = 0.748m.
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The height of the building is 53.4 m (projectile motion)
Explanation:
The motion of the ball is a projectile motion, so it follows a parabolic path which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
First of all, we consider the horizontal motion, which is a uniform motion at constant speed. The equation that gives the horizontal distance travelled is:
where:
is the horizontal velocity of the ball, which is constant since there are no forces in this direction
d = 165 m is the horizontal distance travelled by the ball
Solving for t, we find the time of flight:
Now we analyze the vertical motion: it is an accelerated motion, we can use the suvat equation
where
s is the vertical displacement, which is the height of the building
u = 0 is the initial vertical velocity of the ball
t = 3.3 s is the time of flight
is the acceleration of gravity
Solving for s, we find the height of the building:
Learn more about projectile motion here:
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