On June 8,1999, the national debt of the U.s.a was about $5,608,000,000,000.the population of the United states at the time was about 273,000,000.Suppose the national debt was divided evenly among everyone in the U.S,how much would each person owe ?

Answers

Answer 1
Answer: To figure out the answer, you must divide the debt by the population.

(5,608,000,000,000)/(273,000,000) =20,542.12

Each person would owe $20,542.12.

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Simplify. –10.5 – (–5.3) + 20.2

A.
36

B.
–36

C.
15

D.
–4.4

Answers


so you take -10.5+5.3+20.2=??

-10.5+5.3=-5.2

-5.2+20.2=15

Ur Answer Is 15

Did I Help??

Hope I Did!!


-10.5-(-5.3)+20.2
=-10.5+5.3+20.2
=15

.
..

Jeremy is taking a photography class, but he doesn't own a camera. The class organizers will rent him a camera for $6 per day. Jeremy can spend up to $50 for the class, but he has to pay $15 to register for the class as well as rent the camera. The number of days, d, that Jeremy can rent the camera is represented by the inequality 6d + 15 < 50. How many days can Jeremy rent the camera?a.5
b.6
c.8
d.9
e.10

Answers

5 days since 6*5 equals 30. 30+15= 45. 45 is less than 50.

Answer:

a. 5

Step-by-step explanation:

plato

Nautical flags are used to represent letters of alphabets. The flag for the letter O consists of a yellow right triangle and a red right triangle joined together along their hypotenuse to form a square. The joint hypotenuse of the two triangles is three inches longer than a side of the square. Find the length of a side of the flag. Round your answer to the nearest tenth.

Answers

Answer:

The length of a side of the flag is 7.2inches

Step-by-step explanation:

Let length = x

Let hypotenuse = x+3

UsingPythagoras'Theorem:

x^2 + x^2 = (x+3)^2

x^2 + x^2 = x^2 + 6x + 9

2x^2 = x^2 + 6x + 9

×^2 - 6x - 9 = 0

x =  \frac{ - b +  -  \sqrt{ {b}^(2) - 4ac } }{2a}

x=[-(-6)+sqrt.(-6)^2-4(1)(-9)]/2(1)

×=[6+sqrt.72]/2

×=7.2inches

×=[-(-6)+sqrt.(-6)^2-4(1)(-9)]/2(1)

x=[6-sqrt.72]/2

×=-1.2(rej)

(PS.sqrt is square root)

(Correctmeifiamwrong)

Answer:

7.2 in

Step-by-step explanation:

Let length of side of flag=x

Hypotenuse of right triangle=x+3

According to question information

(x+3)^2=x^2+x^2

Using Pythagoras theorem

(hypotenuse)^2=(base)^2+(perpendicular\;side)^2

x^2+6x+9=2x^2

Using identity: (x+y)^2=x^2+y^2+2xy

2x^2-x^2-6x-9=0

x^2-6x-9=0

Using quadratic formula :x=(-b\pm√(b^2-4ac))/(2a)

x=(6\pm√((-6)^2-4(1)(-9)))/(2(1))

x=(6\pm√(36+36))/(2)

x=(6\pm√(72))/(2)

x=(6\pm6\sqrt2)/(2)

x=(6+6\sqrt2)/(2)=3+3\sqrt2=7.2

x=(6-6\sqrt2)/(2)=3-3\sqrt2

x=-1.24

It is not possible because the length of side is always positive.

Hence, the side of flag=7.2 in

The lengths of two side of a right triangle are given find the length of the third
side

Answers

Answer:

your answer depends on what sides are given.

For example, lets say that you now the lengths of two sides, these being 56 and 24. ( these are just random numbers BTW) to find the third you would add the two lengths that you know and then minus them from 180. So for the example i just typed you would do 56 + 24 first which equals 80, then would do 180-80 which equals 100.

To check your answer, you could do this:

DO THE ABOVE AGAIN CAREFULLY (lol I don't usually check so.. idk)

math is my worst subject so.... hope this helped you.

Answer:

Use the Pythagorean Theorem:  a² + b² = c².

Step-by-step explanation:

For any given right triangle the sum of the measures of the sides squared is equal to the hypotenuse squared.  The formula is call the Pythagorean Theorem and is written:  a² + b² = c², where 'a' and 'b' are the legs of the triangle and 'c' is the hypotenuse.  

Depending on which side of the triangle they give you, you can plug the other two side lengths into the equation to solve for the third.

Points V, W, X, Y, and Z are graphed on a number line. The coordinate of point V is –8. What points are at a distance of 5 units from point V?

Choose all answers that are correct.

A.
W = –13

B.
X = –8

C.
Y = –3

D.
Z = 3

Answers

Using the absolute value:
|x-(-8)|=5\n|x+8|=5\nx+8=5 \vee x+8=-5\nx=-3 \vee x=-13

A and C

Calculate: 2.7·6.2–9.3·1.2+6.2·9.3–1.2·2.7
not pemdas. some shortcut method plz

Answers

Answer:

60

See steps

Step by Step Solution:

More Icon

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "2.7" was replaced by "(27/10)". 8 more similar replacement(s)

STEP

1

:

          27

Simplify   ——

          10

Equation at the end of step

1

:

   27 62   93 12    62 93    12 27

(((——•——)-(——•——))+(——•——))-(——•——)

   10 10   10 10    10 10    10 10

STEP

2

:

          6

Simplify   —

          5

Equation at the end of step

2

:

   27 62   93 12    62 93    6 27

(((——•——)-(——•——))+(——•——))-(—•——)

   10 10   10 10    10 10    5 10

STEP

3

:

          93

Simplify   ——

          10

Equation at the end of step

3

:

   27 62   93 12    62 93   81

(((——•——)-(——•——))+(——•——))-——

   10 10   10 10    10 10   25

STEP

4

:

          31

Simplify   ——

          5

Equation at the end of step

4

:

   27 62   93 12    31 93   81

(((——•——)-(——•——))+(——•——))-——

   10 10   10 10    5  10   25

STEP

5

:

          6

Simplify   —

          5

Equation at the end of step

5

:

   27 62   93 6   2883  81

(((——•——)-(——•—))+————)-——

   10 10   10 5    50   25

STEP

6

:

          93

Simplify   ——

          10

Equation at the end of step

6

:

   27 62   93 6   2883  81

(((——•——)-(——•—))+————)-——

   10 10   10 5    50   25

STEP

7

:

          31

Simplify   ——

          5

Equation at the end of step

7

:

   27   31     279     2883     81

(((—— • ——) -  ———) +  ————) -  ——

   10   5      25       50      25

STEP

8

:

          27

Simplify   ——

          10

Equation at the end of step

8

:

   27   31     279     2883     81

(((—— • ——) -  ———) +  ————) -  ——

   10   5      25       50      25

STEP

9

:

Calculating the Least Common Multiple

9.1    Find the Least Common Multiple

    The left denominator is :       50

    The right denominator is :       25

      Number of times each prime factor

      appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 1 0 1

5 2 2 2

Product of all

Prime Factors  50 25 50

    Least Common Multiple:

    50

Calculating Multipliers :

9.2    Calculate multipliers for the two fractions

  Denote the Least Common Multiple by  L.C.M

  Denote the Left Multiplier by  Left_M

  Denote the Right Multiplier by  Right_M

  Denote the Left Deniminator by  L_Deno

  Denote the Right Multiplier by  R_Deno

 Left_M = L.C.M / L_Deno = 1

 Right_M = L.C.M / R_Deno = 2

Making Equivalent Fractions :

9.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

 L. Mult. • L. Num.      837

 ——————————————————  =   ———

       L.C.M             50

 R. Mult. • R. Num.      279 • 2

 ——————————————————  =   ———————

       L.C.M               50  

Adding fractions that have a common denominator :

9.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

837 - (279 • 2)     279

———————————————  =  ———

     50            50

Equation at the end of step

9

:

 279    2883     81

(——— +  ————) -  ——

 50      50      25

STEP

10

:

Adding fractions which have a common denominator

10.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

279 + 2883     1581

——————————  =  ————

   50          25

Equation at the end of step

10

:

1581    81

———— -  ——

25     25

STEP

11

:

Adding fractions which have a common denominator

11.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

1581 - (81)     60

———————————  =  ——

   25          1

Final result :

60

Answer:

2222222222

Step-by-step explanation: