In a poker hand consisting of 5 cards find the probability of holding

Answers

Answer 1

Answer: holding what.......? can u be more specific?

Related Questions

Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 33.0 and half the distance at 80.0 . On her return trip, she drives half the time at 33.0 and half the time at 80.0 . What is Julie's average speed on the way to Grandmother's house? What is her average speed on the return trip?
An equation whose _____ are polar coordinates is called a polar equation.
the sum of present ages of ria and abby is 48 years. today abby is 4 years older than shweta. the respective ratio of the present ages of ria and shweta is 4: 7. what was abby's age two years ago?
For which of the following sequences is it true that every term (after the first one) is 4 less than the previous term A. -3,1,5,9B. 9,5,1,3C. 7,3,-1,-5D. 8,4,8,4
Which shows one way to determine the factors of x3 + 5x2 – 6x – 30 by grouping?

Find the solutions to sin2(x) + cos(x) = 1, keeping 0 ≤ x < 2π

Answers

sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}

Answer:

Which statements did you include in your answer?

Isolate sin(x) by adding 4 and taking the square root of both sides.

State that sin(x) = 2 or sin(x) = –2.

State that –2 and 2 are undefined values of the inverse sine function.

There are no solutions because –2 and 2 are not in the domain of the function.

Step-by-step explanation:

Find the equivalent fraction for 10/20

Answers

$(10)/(20) = ( (10)/(10) )/( (20)/(10) ) = (1)/(2)$

Find dy/dx if y= (1+x)e^x^2

Answers

$y=(1+x)e^(x^2)\ny'=(1+x)'\cdot e^(x^2)+(1+x)\cdot(e^(x^2))'\ny'=1\cdot e^(x^2)+(1+x)\cdot e^(x^2)\cdot (x^2)'\ny'=e^(x^2)+(1+x)e^(x^2)\cdot2x\ny'=e^(x^2)(1+(1+x)\cdot2x)\ny'=e^(x^2)(1+2x+2x^2)\ny'=e^(x^2)(2x^2+2x+1)\n$

You first need to know that:

$If\quad y=u\cdot v\n \n \frac { dy }{ dx } =u\frac { dv }{ dx } +v\frac { du }{ dx } \n \n$

Knowing that u is a function of x and that v is a function of x.

So:

$y=\left( 1+x \right) { e }^{ { x }^( 2 ) }=u\cdot v\n \n u=1+x,\n \n \therefore \quad \frac { du }{ dx } =1$

$\n \n v={ e }^{ { x }^( 2 ) }={ e }^( p )\n \n \therefore \quad \frac { dv }{ dp } ={ e }^( p )={ e }^{ { x }^( 2 ) }\n \n p={ x }^( 2 )\n \n \n \therefore \quad \frac { dp }{ dx } =2x$

$\n \n \therefore \quad \frac { dv }{ dp } \cdot \frac { dp }{ dx } =2x{ e }^{ { x }^( 2 ) }=\frac { dv }{ dx }$

And this means that:

$\frac { dy }{ dx } =\left( 1+x \right) \cdot 2x{ e }^{ { x }^( 2 ) }+{ e }^{ { x }^( 2 ) }\cdot 1\n \n =2x{ e }^{ { x }^( 2 ) }\left( 1+x \right) +{ e }^{ { x }^( 2 ) }$

$\n \n ={ e }^{ { x }^( 2 ) }\left( 2x\left( 1+x \right) +1 \right) \n \n ={ e }^{ { x }^( 2 ) }\left( 2x+2{ x }^( 2 )+1 \right) \n \n ={ e }^{ { x }^( 2 ) }\left( 2{ x }^( 2 )+2x+1 \right)$

(Sorry for the spam, making sure these are right) One zero of the polynomial function f(x)=x^3-9x^2+20x is x=0. What are the polynomial function? Choices:

Answers

Replace f(x) with 0 and solve for x. We do this because the x intercepts always occur when y = 0. Keep in mind that y = f(x).

f(x)=x^3-9x^2+20x

0=x^3-9x^2+20x

x^3-9x^2+20x = 0

x(x^2-9x+20) = 0 .... factor out GCF x

x(x-5)(x-4) = 0 ... factor the stuff inside

x = 0 or x-5 = 0 or x-4 = 0 ... zero product property

x = 0 or x = 5 or x = 4

The roots or zeros are 0, 5, 4

Answer: Choice D

In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square? Numerical Answers Expected! Answer for Blank 1:

Answers

(x² - 6x +...)
a² - 2ab + b²

[1x² + 2* 1 *(-3) + (-3)²]

coefficient b trójmianu square of the product of the coefficients a and b and number 2

canonical form of the function
f(x) = 4 * (x - 3)² + 20

What is the inverse function of f(x)=6x^3-3?

Answers

f(x)=6x^3-3

1. Replace f(x) with y: y = 6x^3 - 3
2. Interchange x and y: x = 6y^3 - 3 x+3 x+3
3. Solve this result for y: y^3 = --------- or y = cube root of -------
-1 6 6
4. Replace y with f (x)

Other Questions

The product of 5 more than p and 7?

Wheels are 1.25 inches in diameter covert the wheels diameter to feet

What is equivalent to 49^3/4?

Henrietta buys twelve pounds of bananas and ten pounds of apples for $ 12 . Gustavo buys eight pounds of bananas and five pounds of apples for $ 7 . What is the price per pound of bananas and apples?