In 4 years, harry’s age will be the same as jim’s age is now. in 2 years, jim will be twice as old as harry will be. find their ages now.

Answers

Answer 1

Answer: The answer to this question would be:
Jim =6 years
Harry =2 years

To answer this question, you need to translate the description into a mathematical equation. If H= Harry's ages and J= Jim's ages, then the equation should be look like this:

1. H+4= J
2. (J+2)= 2(H+2)
J+2= 2H+4
J= 2H +2

If you put the 1st and 2nd equation together, the result would be:
H+4= J
H+4= (2H +2)
H-2H= 2-4
-H= -2
H=2

After that insert the H value to either 1st or 2nd equation.
H+4= J
2+4=J
J= 6

Answer 2

Answer:

harry is 2 jim is 6

Step-by-step explanation:

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Simplify.

n 6 · n 5 ÷ n 4 · n 3 ÷ n 2 · n

Answers

Answer: $n^(9)$

Step-by-step explanation:

Given expression: $n^6\cdot n^5/ n^4\cdot n^3/ n^2\cdot n$

The law of exponents are given by :_

$a^m\cdot a^n=a^(m+n)\n\na^m/ a^n=a^(m-n)$

Using PEDMAS, first we solve division, we get

$n^6\cdot n^(5-4)\cdot n^(3-2)\cdot n\n\n=n^6\cdot n\cdot n\cdot n$

Now, using product law of exponent we get

$n^(6+1+1+1)\n\n=n^(9)$

Answer:

The given expression $n^6\cdot n^5/ n^4\cdot n^3/ n^2\cdot n$ is $n^9$

Step-by-step explanation:

Given : Expression $n^6\cdot n^5/ n^4\cdot n^3/ n^2\cdot n$

We have to write the simplified form for the given expression $n^6\cdot n^5/ n^4\cdot n^3/ n^2\cdot n$

Consider the given expression $n^6\cdot n^5/ n^4\cdot n^3/ n^2\cdot n$

Rewrite it in simpler form, we have,

$n^6\cdot(n^5)/(n^4)\cdot (n^3)/(n^2)\cdot n$

Apply exponent rule, $\:a^b\cdot \:a^c=a^(b+c)$ , we have,

$n^6n=\:n^(6+1)$

$=(n^5)/(n^4)\cdot (n^3)/(n^2)n^(7)$

Apply exponent rule, $(x^a)/(x^b)=x^(a-b)$

$(n^5)/(n^4)=n^(5-4)$

$(n^3)/(n^2)=n^(3-2)$

Expression becomes,

$=n^7nn$

Again apply exponent rule, we have,

$\:a^b\cdot \:a^c=a^(b+c)$

$=n^(1+1+7)=n^9$

Thus, The given expression $n^6\cdot n^5/ n^4\cdot n^3/ n^2\cdot n$ is $n^9$

The United States consumes 2.6 billion cases of bottled water per year. Assume that each case holds 24 ½-liter bottles. Each case is 10.2 inches tall, 15.1 inches long and 8.3 inches wide. If all of these cases were lined up end-to-end at the equator, how many times would they go around the earth? What would be the perimeter and area of the base of all of these cases together? The volume?
Note: The circumference of the earth’s equator is 24,901 miles. 1 mile = 5280 feet

Answers

so first find the circumfernece of the earth which is 24,901 times 5280
use a calculator
24,901 times 5280=131,477,280ft
1 ft=12 inches so 131,477,280 times 12=157,727,360 in
so 157,727,360 divide by the legnth of the case=1,577,727,360/15.1=104,485,255.62914 cases to go around the earth once so
million=1000 thousand
billion=1000 million
billion=1,000,000,000
2.6 billion=2,600,000,000
so 2,600,000,000/104,458,255.62914=24.88 or rounded up they would go around the earth close to 25 times

AREA OF THE BASES
base=legnth times width so 15.1 times 8.3 =125.33 in^2
multiply 125.33 in^2 by 2,600,000,000 and get 325,858,000,000 in^2 or 3.25858 times 10^11=area of the bases

PERIMETER OF THE BASES
perimeter of the bases 2Legnth+2Width times 2.6 billion
2(15.1)+2(8.3)=46.8
46.8 times 2.6 billion=121,680,000,000 inches or 1.2168 times 10^11= perimeter of all the bases

VOLUME
24 1/2 liter bottles means 24 times 1/2=12 liters in each pack
2.6 billion times 12=31,200,000,000 liters or 3.12 times 10^10

Ship A receives a distress signal from the southwest, and ship B receives a distress signal from the same vessel from the north. At what location is the vessel in distress located? Describe how you arrived at your conclusion using complete sentences. You must show all work in order to receive credit.

Answers

g=t negative 320+f5 t=b

What is the perimeter of a rhombus-shaped street sign with 35-cm side?

Answers

rhombus has 4 sides htat are equal legnth
if 1 side is 35
all 4 sides are 35
perimiter=legnth around=4 times 35=140
answer is 140cm

A rocket lifted off from a launch pad and traveled vertically 30 km, then traveled 40 km at 30 degrees from the vertical, and then traveled 100 km at 45 degrees from the vertical. At that point, the rocket was how many kilometers above the height of the launch pad?

Answers

Well, we are told that in the beginning, it has traveled 30km vertically, so do not forget to add that on at the end.

Next it says that it traveled 40km 30 degrees from vertical, so we set up a sin equation to solve for the missing side, n:

sin(angle)= opposite/hypotenuse:

sin(30) = n/40

40sin30=n

n=20km

Then it says at an angle of 45 degrees, it goes 100km. This means that we are given the hypotenuse of a right triangle, and we need to find the side that goes up and down. We shall call this length x.

We know that the angle opposite x is 45 degrees.

So, we will use sin to solve for x:

sin(angle)= opposite/hypotenuse

sin45= x/100

100sin45=x

x=70.711km

But remember, I said not to forget about that 30km from the very beginning? So we add up all of our vertical heights:

30km + 20km+ 70.711km = 120.711km

Write a conjecture for the following situation - the product of three odd numbers.

Answers

Answer:

Step-by-step explanation:

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