the price of a tent was decreased by 15% and sold for 76.49. What was the original price of the tent in dolars?
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Related Questions
Which one is the correct answer
Explain how you would construct a perpendicular bisector of WX using a compass and a straightedge. (31 points guys)
When the sum of 8 and a certain number is increased by 12, the result is the same as the product of 3 and the number. What is the number?
There were four apples. Three apples fell from the tree. How many apples are on the tree now?
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-98.6/3.8=-25.94 because if you line the decimals up and then add them you will get -25.94
-98.60
+ 3.80
-25.94
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Answer:
Solve for x by simplifying both sides of the inequality, then isolating the variable.
Inequality Form:
x>10
Interval Notation:
(10,∞)
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Answer:
a. 1 =ST; 20 = RS;5 = x
b. 40 = ST; 20 = RS; 12 = x
c.17 = RT;6 = RS; 7 = x
d. 34 = RT; 15 = RS; 6 = x
Step-by-step explanation:
___
Since the exercise ONLY tells you that PointSis inbetweenRT,use the SegmentAdditionPostulate for all exercises:
d.8x - 14 = 19 + [4x - 9]
8x - 14 = 10+ 4x(Combine like-terms)
- 8x-8x
___________________
-14 = 10 - 4x
-10-10
_____________
-24 = -4x
________
-4-4
6 = x[Plug this back into the equations above to get these measures: 34 = RT; 15 =RS]
c.x+ 10 = 11 + [2x - 8]
x+10 = 3+ 2x(Combine like-terms)
-2x-2x
________________
-x + 10 = 3
- 10-10
___________
-x= -7
____
-1-1
x = 7 [Plug this back into the equations above to get these measures: 17 = RT; 6 = RS]
b.60 = [4x - 8] + [3x - 16]
60 = 7x-24(Combine like-terms)
+24+ 24
______________
84 = 7x
______
77
12 = x[Plug this back into the equations above to get these measures: 40 = ST; 20 = RS]
a.21 = [x - 4] + [2x + 10]
21 = 3x+6(Combine like-terms)
-6- 6
______________
15 = 3x
______
33
5 = x[Plug this back into the equations above to get these measures: 1 = ST; 20 = RS]
I am delighted to assist you anytime.
To solve for x and find the lengths RS, ST, and RT, we can set up an equation using the given information. Using the equation RS + ST + RT = 0 and substituting the given values, we can simplify the equation to find x. With the value of x, we can then find the lengths RS, ST, and RT. Therefore, RS = -8, ST = -13, and RT = 21.
To write an equation in terms of x, we need to set up an equation using the given information RS = 2x + 10, ST = x - 4, and RT = 21.
We can start by writing the equation RS + ST + RT = 0.
Substituting the given values, we get (2x + 10) + (x - 4) + 21 = 0. Simplifying this equation, we have 3x + 27 = 0.
Solving for x, we subtract 27 from both sides and divide by 3, to get x = -9.
With the value of x, we can now find the lengths RS, ST, and RT. RS = 2(-9) + 10 = -8, ST = (-9) - 4 = -13, and RT = 21.
Therefore, RS = -8, ST = -13, and RT = 21.
For more such questions on equations, click on:
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O B. b<1
O c. b< 0
O D. b>0
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Answer:
the answer is A. b>1
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Approximate circumference of a semicircle with a radius of 30 centimeters is 94.2 centimeter
Solution:
Given semicircle with a radius of 30 centimeters
To find: approximate circumference of a semicircle
To find circumference of semicircle we can divide the circumference of circle by 2
circumference of semicircle = circumference of circle 2
Substituting the given radius = 30 cm,
Thus approximate circumference of a semicircle with a radius of 30 centimeters is 94.2 centimeter
Answer:
94.2
Step-by-step explanation:
Math 5 ( Section F,G or X)
History 5 (section T,U or Y)
Biology 1 ( section D,H,V or W)
if she will enroll in all of these subjects, in how many ways can she arrange her schedule?
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each time
first slot we have all of them so
4 choices=1st slot
3 choices=2nd slot (1 was taken for 1st slot)
2 choices
1 choice
multiply
4 times 3 times 2 times 1=24
answe ris 24 ways
From the other answer, I see that my colleague with the busted clock
interpreted your question in a different way. So I should explain
how I understand your question.
I understand you to say that both English sections meet at the
same time, all 3 math sections meet at the same time, all 3 History
sections meet at the same time, and all 4 Biology sections meet at
the same time. So our student will take the subjects in that order,
but for each period, she can choose which section to join.
If that's not the right way to understand the question, then it's definitely
too complicated for me.
Reading it MY way,
here's the solution:
English: 2 choices. For each of those . . .
Math: 3 choices. For each of those . . .
History: 3 choices. For each of those . . .
Biology: 4 choices.
Total possible different line-up of sections:
(2 x 3 x 3 x 4) = 72 different line-ups.