This equation has an infinite number of solutions, so it will be categorized as an identity.
Answer:
unlimited
Step-by-step explanation:
right on khan
Is it dependant or independant and why?
Answer:
4j^3 + 5j^2 + 7j - 1
Step-by-step explanation:
(8j^3 - 3j^2 + 5)-(4j^3+8j^2+7j-6)
Distribute the -1 in front of the (4j^3+8j^2+7j-6)
8j^3 - 3j^2 + 5 - 4j^3 + 8j^2 + 7j - 6
We can combine anything with the same exponent number that "j" is raised to
8j^3 - 4j^3 = 4j^3
-3j^2 + 8j^2 = 5j^2
7j is just 7j since there is nothing else with just j in it
5 - 6 = -1
Add these together
4j^3 + 5j^2 + 7j - 1 is our final answer