Tomas drew a rectangle with an area of 6 cm² what is the greatest possible perimeter for this rectangle
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The greatest perimeter would be 12 cm
Does any one know the answer i just got started in this stuff: Write an equation in sloper-intercept form for the following line:y-intercept 3 and slope 3?
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Slope intercept form: Y= mx +b m is the slope b is the y-intercept in this case, just plug the numbers into the equation
Answer is Y= 3x + 3
Plz help... 6b - 49 =2(b - 3)
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You always start by simplifying. 6b-49=2(b-3) becomes 6b-49=2b-6 From there you can group the b's together by subtracting 2b from both sides, leaving you with 4b-49=-6 Now you can get the b's alone by adding 49 (to cancel out -49) to both sides, giving you 4b=43, You're still trying to get b by itself, so what you'll do is divide both sides by 4, giving you b=10.75
Which correctly gives the location of the point (7, –13)? A. Quadrant I B. Quadrant II C. Quadrant III D. Quadrant IV
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The answer is D. because the x-value is positive and the y-value is negative
What is the greatest perimeter of a rectangle with an area of 39 sq. ft.?
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To find the answer you do 39×4. You multiply by 4 because there are 4 sides.
This will be the biggest number.
Rectangle A: -- Length = 20-ft, Width = 10-ft. -- Area = 200 square ft -- Perimeter = 60-ft
Rectangle B: -- Length = 16-ft, Width = 12.5-ft -- Area = 200 square ft -- Perimeter = 57-ft
Rectangle C: -- Length = 40-ft, Width = 5-ft -- Area = 200 square ft -- Perimeter = 90-ft
Rectangle D: -- Length = 50-ft, Width = 4-ft -- Area = 200 square ft -- Perimeter = 108-ft
Rectangle E: -- Length = 100-ft, Width = 2-ft -- Area = 200 square ft -- Perimeter = 204-ft