Isotopic Natural
Mass Abundance
Number %
1 39 78.8
2 40 18.1
3 41 3.1
what is the atomic weight
The atomic weight of a hypothetical element with isotopes of masses 39, 40, and 41 and natural abundances of 78.8%, 18.1%, and 3.1% respectively, is approximately 39.243 atomic mass units (amu).
To calculate the atomic weight of an element from its isotopes' masses and abundances, use the formula: atomic weight = (mass1 x abundance1) + (mass2 x abundance2) + ... (massn x abundancen), where the masses are the isotopes' masses and the abundances are given as proportions (i.e., percentages divided by 100).
Using the values from your question, the calculation would be as follows:
Atomic weight = (39 x 0.788) + (40 x 0.181) + (41 x 0.031) = 30.732 + 7.24 + 1.271 = 39.243. So, the atomic weight of the hypothetical element is approximately 39.243 atomic mass units (amu).
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What is the [H+] after the change?
Answer:
2
Explanation:
Answer:
The correct answer is A) carbon-carbon bonds.
Explanation:
The noncovalent interactions can generally be classified into electrostatic, π interactions, Van der Waals forces, and hydrophobic interactions. They do not share electrons, but present more dispersed variations of electromagnetic interactions between molecules or within the same molecule.
In a carbon-carbon bond, there is a covalent bond between two atoms in an organic compound. The most common form is the simple bond, which is composed of two electrons, one belonging to each of the two atoms. The simple carbon-carbon bond is a sigma bond.
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Answer:
The correct option is A
Explanation:
Non-covalent interactions, from the name, means interactions that do not involve covalent interaction. Covalent interaction involves the sharing of electrons between two atoms. The bond between two carbons in organic compounds is covalent bond. The covalent interaction in itself does not permit for three-dimensional structure. Examples of noncovalent interaction include hydrogen bonds, ionic interactions, van der waals interactions and hydrogen bonds