The distance between each tree planted along the 2 kilometers and 50 meters road is 205 meters. This is achieved by dividing the length of the road (2050 meters) by the number of spaces between the trees (10).
To solve this problem, first, we need to understand that a kilometer is equal to 1000 meters. Therefore, 2 kilometers 50 meters is equal to 2050 meters. Given that the 11 trees are planted at an equal distance apart along the 2050 meter road, we would have to divide the total road length by the number of spaces between the trees. The number of spaces is always one less than the number of trees, so we have 11-1 = 10 spaces. Therefore, the distance between each tree is 2050 meters divided by 10, which equals to 205 meters.
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Answer:
-9.5
Step-by-step explanation:
2x + 21 =
2x + 20 = 1 (C.P)
2x = 1-20
2x = - 19
x= - 19/2
x = - 9. 5
B. ( x - 3, y - 2)
C. ( x + 3, y - 2)
D. ( x - 3, y + 2)
Answer:
C. ( x +3, y -2)
System of equations that can be used to find the price of one drink and the price of one bag of popcorn is:
3d + 10p = 41
2d + 2p = 11
Price of a bag of popcorn is $ 3.5
Let "d" be the price of one drink
Let "p" be the price of 1 bag of popcorn
Luke spends total of $41 on three drinks and 10 bags of popcorn
3 drinks x price of one drink + 10 bags of popcorn x price of 1 bag of popcorn = 41
3d + 10p = 41 ------ eqn 1
Christopher spend a total of $11 on two drinks and two bags of popcorn
2 drinks x price of one drink + 2 bags of popcorn x price of 1 bag of popcorn = 11
2d + 2p = 11 ------- eqn 2
Eqn 1 and eqn 2 represents system of equations that can be used to find the price of one drink and the price of one bag of popcorn
Let us solve eqn 1 and eqn 2 to find values of "d" and "p"
Multiply eqn 2 by 5
10d + 10p = 55 --- eqn 3
Subtract eqn 3 from eqn 1
3d + 10p = 41
10d + 10p = 55
(-) ------------------------
-7d = -14
d = 2
From eqn 2,
2d + 2p = 11
2(2) + 2p = 11
4 + 2p = 11
2p = 7
p = 3.5
Thus price of 1 bag of popcorn is $ 3.5 and price of one drink is $ 2