MATHEMATICS HIGH SCHOOL

If the radius of a circle is 8 ft, what is the length of the diameter? 8 ft 24 ft 4 ft 16 ft

Answers

Answer 1

Answer: 16 ft bc u would times by 2

Answer 2

Answer:

Given that:

Radius= 8ft

Tofind:

The diameter of the given circle.

Solution:

Diameter is twice the radius. ( radius ×2)

$\large\boxed{\bold{d= r ×2}}$

In this question all the required values are given so we'll simply have to solve.

Let's substitute the values according to the formula.

$\bold{d= 8×2}$

$\large\boxed{\bold{d= 16 \ ft}}$

Therefore, the diameter of the given circle is 16 ft.

Answer=OptionD

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O,60 is the same rotation as O, A. -300 B. 120 C. 300
Which amount is largest? 100 g 1 kg 1,000 mg 1 dg
Given: ∠A and ∠B are complementary angles. m∠A=3x+105 ; m∠B=−6x−39 Prove: m∠B=9° Drag and drop reasons into the boxes to correctly complete the proof. Statement Reason ∠A and ∠B are complementary angles. Given m∠A=3x+105 ; m∠B=−6x−39 Given m∠A+m∠B=90° Definition of complementary angles 3x+105−6x−39=90 Substitution Property of Equality −3x+105−39=90 Simplify. −3x+66=90 Simplify. −3x=24 x=−8 m∠B=−6(−8)−39 m∠B=48−39 Simplify. m∠B=9°
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Divide £10 into the ratio 2:3

Answers

add the ratio together in this case 2+3. then divide the number by that. in this case 60/5. with that number, in this case 12, multiply this number bu the ratio.. (12*2) : (12*3) it will give you a ratio of 24:36

2+3=5
2/5*60=12*2=24
3/5*60=12*3=36 =24:36

A contractor has 48 meters of fencing to use as the perimeter of a rectangular garden. The length of one side of the garden is represented by x, and the area of the garden is 108 square meters. Determine, algebraically, the dimensions of the garden in meters

Answers

if we let y be the dimension of the other side, then the perimeter has the formula
P = 2x + 2y
48 = 2x + 2y

The area of the rectangle has the formula
A = xy
108 = xy

So,
x = 108/y

Substituting this to the first equation
48 = 2(108/y) + 2y
48y = 216 + 2y^2
2y^2 - 48y + 216 = 0

Solving the quadratic equation:
y = 18 or 6

Either of the two is the correct answer for y, the value of x would just be the other. So, the dimensions of the garden is
18 m x 6 m

Marian se deplaseaza ,cu automobilul,pe autostrada.La ora 10 si 35 minute el se afla la kilometrul 25 .Dupa un interval de timp,la ora 11 si 15 minute,el se afla la kilometrul 100.Calculati :durata deplasarii,distanta parcursa de Marian si viteza medie a acestuia(exprimata in unitati de SI)

Answers

Step-by-step explanation:

If Marian travels, by car, on the highway. At 10 and 35 minutes he is at kilometer 25. After a period of time, at 11 and 15 minutes, he is at kilometer 100.

Total distance covered = 25km + 100km

Total distance covered by Marian = 125km

Total time taken by marian = 10hr 35min + 11hr + 15min

Total time taken by marian = (10+11)hr + (35+15)min

Total time taken by marian = 21hr 50mins

Total time taken by marian = 21 * 50/60 hr

Total time taken by marian (Duration) = 21.833hr

Average speed = Total distance covered/Total time taken

Average speed = 125/21.833

Average speed = 5.725km/hr

Convert to m/s

5.725km/hr = 5.725*1000/3600

5.725km/hr = 5725/3600

5.725km/hr = 1.5903 m/s

Hence the average speed expressed in SI unit is 1.5903 m/s

What is the median of 37, 39,40, 42,42, 45, 48, 49, 51, 52?

Answers

To find a median, first order the numbers from least to greatest, or vice versa.
Then, the middle number in that sorted list is the median.

But, this list is already sorted.
So, the median is 42 & 45.

Technically, the answer is 42 & 45.

The middle of 42 & 45, however, is 43.5

Hope this helped!

The median is ...........
43.5

AA, BBB, and CCC are collinear, and BBB is between AAA and CCC. The ratio of ABABA, B to BCBCB, C is 1:21:21, colon, 2. If AAA is at (7,-1)(7,−1)left parenthesis, 7, comma, minus, 1, right parenthesis and BBB is at (2,1)(2,1)left parenthesis, 2, comma, 1, right parenthesis, what are the coordinates of point CCC?

Answers

Answer:

The coordinates of point C are (-8,5).

Step-by-step explanation:

It is given that A, B and C collinear and B is between A and C.

The ratio of AB to BC is 1:2. It means Point divided the line segments AC in 1:2.

Section formula:

$((mx_2+nx_1)/(m+n),(my_2+ny_1)/(m+n))$

The given points are A(7,-1) and B(2,1).

Let the coordinates of C are (a,b).

Using section formula the coordinates of B are

$B=(((1)(a)+(2)(7))/(1+2),((1)(b)+(2)(-1))/(1+2))$

$B=((a+14)/(3),(b-2)/(3))$

We know that point B(2,1).

$(2,1)=((a+14)/(3),(b-2)/(3))$

On comparing both sides we get

$2=(a+14)/(3)$

$6=a+14$

$6-14=a$

$-8=a$

The value of a is -8.

$1=(b-2)/(3)$

$3=b-2$

$3+2=b$

$5=b$

The value of b is 5.

Therefore, the coordinates of point C are (-8,5).

The coordinates of the pointC such that pointsA and B are (7, -1) and (2, 1) and the ratioAB to BC is 1 : 2 is (-8, 5).

How to determine the location of a point within a line segment

According to the Euclidean geometry, a line is formed by two points on a plane and three points are collinear if all the three points go through a single line.

By definitions of vector and ratio we derive an expression to determine the coordinates of the point B:

$\overrightarrow{AB} = (1)/(1+2)\cdot \overrightarrow{AC}$

$\vec B - \vec A = (1)/(3)\cdot \vec C -(1)/(3)\cdot \vec A$

$(1)/(3)\cdot \vec C = \vec B - (2)/(3)\cdot \vec A$

$\vec C = 3 \cdot \vec B - 2\cdot \vec A$

If we know that A(x,y) = (7, -1) and B(x,y) = (2, 1), then the coordinates of point C is:

C(x, y) = 3 · (2, 1) - 2 · (7, -1)

C(x, y) = (6, 3) + (- 14, 2)

C(x,y) = (- 8, 5)

The coordinates of the pointC such that pointsA and B are (7, -1) and (2, 1) and the ratioAB to BC is 1 : 2 is (-8, 5).

Remark

The statement is poorly formatted and reports mistakes. Correct form is shown below:

A, B and C are collinear and B is between A and C. The ratio of AB to BC is 1 : 2. If A is A(x, y) = (7, -1) and B(x, y) = (2, 1), what are the coordinates of point C?

To learn more on line segments, we kindly invite to check this verified question: brainly.com/question/25727583

How many ways are there to distribute three different teddy bears and nine identical lollipops to four children (a) Without restriction? (b) With no child getting two or more teddy bears? (c) With each child getting three ""goodies""?