To write an improper fraction as a mixed number, divide the denominator into the numerator. For example, 9/5 to a mixed number would be 1 and 4/5.
Image provided.
Answer:
45 fake dollar.
Step-by-step explanation:
Given: teacher offer 5 fake dollar for each perfect score in Math test.
One of Student get perfect score on 4 maths test.
Student already have 25 fake dollor.
Now, solving to find total number of fake dollar teacher offered to student.
As given teacher offer 5 dollar for each perfect score in maths test and student got perfect score on 4 maths test.
Number of fake dollar offer to the student= ∴ Number of fake dollar offered to the student=
We know, student already have 25 fake dollar.
Next, finding total number of fake dollar student have.
Total fake dollar student have= .
Total fake dollar student have=
Hence, student have total 45 fake dollar to spend in the class store.
Fifth degree polynomial; scary stuff. We know it has five complex roots, counting multiplicities. How many are real?
The rational root test tells us we only have to try the divisors of 9, so 1, -1, 3, -3, 9, -9. We find x=3 gives
243 - 243 - 54 + 54 - 9 + 9 = 0
in nice pairs.
So x-3 is a factor and we can divide to get a 4th degree polynomial. The division is a bit easier than usual.
x^4 - 2x^2 - 3
x - 3 | x^5 - 3x^4 - 2x^3 + 6x^2 - 3x + 9
x^5 - 3x^4
0 - 2x^3 + 6x^2
0 - 3x + 9
0
So we get
It's downhill from here. The new factor is really just a quadratic in x squared, and factors easily:
And now if we descend into irrational and complex numbers, we can further factor
and we can read off our roots,
We have one rational root, namely 3, and two irrational roots, the square roots of three, and two purely imaginary roots.
Answer: 1 rational, 2 irrational
Answer:
One rational and 2 irrational zeroes
Step-by-step explanation:
I agree with the other guy.
f(3) = 0 so x = 3 is a rational root.
There also are 2 irrational roots and 2 complex roots.
.
.
b 75.7
c 85.7
d 40
75.7 I think that is the answer
To find the mean absolute deviation, calculate the absolute difference between each value and the mean, then find the average of those absolute differences.
To find the mean absolute deviation for the given set, follow these steps:
In this case, the mean of the set is (65+90+85+70+70+95+55)/7 = 74.29
The absolute differences between each value and the mean are: |65-74.29|, |90-74.29|, |85-74.29|, |70-74.29|, |70-74.29|, |95-74.29|, |55-74.29| which simplify to 9.29, 15.71, 10.71, 4.29, 4.29, 20.71, 19.29
The sum of the absolute differences is 84.29
Finally, divide the sum by the total count: 84.29/7 = 12.04
So, the mean absolute deviation for the given set is approximately 12.04
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