MATHEMATICS MIDDLE SCHOOL

Solve each system using elimination PLEASE HELP!!!1.8X+5Y=6
3X-2Y=10
2.-3x+8y=10
5y+6y=80
3. 4x+12y=-24
3x-6y=-18
4.5x-6y=48
2x+5y=-3
please help show all work

Answers

Answer 1
Answer: 1.
8x+5y=6 \ \ \ |* 2 \n3x-2y=10 \ \ \ |* 5 \n \n16x+10y=12 \n\underline{15x-10y=50} \n16x+15x=12+50 \n31x=62 \ \ \ |/ 31 \nx=2 \n \n3x-2y=10 \n3 * 2-2y=10 \n6-2y=10 \ \ \ |-6 \n-2y=4 \ \ \ |/ (-2) \ny=-2 \n \n(x,y)=(2,-2)

2.
-3x+8y=10 \ \ \ |* 5 \n5x+6y=80 \ \ \ |* 3 \n \n-15x+40y=50 \n\underline{15x+18y=240 \ \ } \n40y+18y=50+240 \n58y=290 \ \ \ |/ 58 \ny=5 \n \n5x+6y=80 \n5x+6 * 5=80 \n5x+30=80 \ \ \ |-30 \n5x=50 \ \ \ |/ 5 \nx=10 \n \n(x,y)=(10,5)

3.
4x+12y=-24 \n3x-6y=-18 \ \ \ |* 2 \n \n4x+12y=-24 \n\underline{6x-12y=-36} \n4x+6x=-24-36 \n10x=-60 \ \ \ |/ 10 \nx=-6 \n \n3x-6y=-18 \n3 * (-6)-6y=-18 \n-18-6y=-18 \ \ \ |+18 \n-6y=0 \ \ \ |/ (-6) \ny=0 \n \n(x,y)=(-6,0)

4.
5x-6y=48 \ \ \ |* 2 \n2x+5y=-3 \ \ \ |* (-5) \n \n10x-12y=96 \n\underline{-10x-25y=15} \n-12y-25y=96+15 \n-37y=111 \ \ \ |/ (-37) \ny=-3 \n \n2x+5y=-3 \n2x+5 * (-3)=-3 \n2x-15=-3 \ \ \ |+15 \n2x=12 \ \ \ |/ 2 \nx=6 \n \n(x,y)=(6,-3)

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A boy runs 9/10 of a mile in 5 minutes. How many miles does he run in 1 minute?

Answers

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Answers

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a student claims that the equation y=7 is not a linear equation because it does not have the from y=m x+b.do you agree or disagree?why?

Answers

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What is the kinetic energy of a jogger with a mass of 65.0 kg traveling at a speed of 2.5 m/s

Answers

The kineticenergy describes the energyexhibited by a body due to its motion.The kineticenergy of the jogger is 203.125 Joules

Recall :

  • Kineticenergy=0.5mv²
  • Mass,m=65kg
  • Velocity,V=2.5m/s

Hence, the kinetic energy of the jogger can be calculated thus :

K. E = 0.5 × 65 × 2.5²

K. E = 0.5 × 65 × 6.25

K. E = 203.125Joules

Therefore, thekineticenergyof the jogger is 203.125joules

Learn more : brainly.com/question/18405415
KE = 1/2mv^2

KE = 1/2(65)*2.5^2
KE = 32.5*2.5^2

KE = 203.125 Joules

The kinetic energy is equal to 203.125 J. 

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Answers

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Simplify a7/a4

A) 1/a3
B)-a/a2
C)a4/a3
D)a3

Answers

Answer: a^3


Step-by-step explanation: Reduce the expression by cancelling the common factors

Hope this helps! :) ~Zane

Answer:

=a3

Step-by-step explanation:

a7

a4

=

a7

a4

=

a*a*a*a*a*a*a

a*a*a*a

=a*a*a

=a3
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IM BEGGING PLEASE HELP I GIVE THANKS