y = −x2
one quadratic graph opening down and one quadratic graph opening up. They intersect at 1, negative 1 and negative 1, negative 1.
one quadratic graph opening up and one quadratic graph opening down. They intersect at 0, negative 3.
two quadratic graphs opening up. They intersect at 0, negative 3.
quadratic graph opening up and quadratic graph opening down. They intersect at 1, 2 and negative 1, 2
one quadratic graph opening down and one quadratic graph opening up. They intersect at 1, negative 1 and negative 1, negative 1
i.e. they intersect at (1,-1) and (-1,-1)
We are asked to find which graph correctly solves the system of quadratic equations:
and
on solving the equation by the method of substitution i.e. on equating both the equations we get:
Now on putting the value of x in any of the equations we get the value of y as:
Hence, the point of intersections of both the graph is:
(1,-1) and (-1,1).
Also the graph of the quadratic equation:
opens upward.
and graph of the quadratic equation:
opens downward.
B)
8
(6 + 3)
C) 5(2) + 2(6 x 3)
Eliminate
D) 5(2 + 3) - 4(8 + 1)
Answer:
thank you
Step-by-step explanation:
Answer:
Step-by-step explanation:
We have been given a function:
We will compare it with the genral equation which is:
Where, a is amplitude and period of function is
In given equation a is -3 and b is 4
So, period of the given equation is:
Yo can look at the graph in the attachment.
The a is the amplitude and the period of the function is
We have been given a function
We will compare it with the general equation which is
Where a is amplitude and period of the function is
In the given equation a is -3 and b is 4
So, the period of the given equation is:
You can look at the graph.
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