35, 0.68, 0.20, 0.31 ordered greatest to least

Answers

Answer 1
Answer: 0.20, 0.31, 0.68, 35.0

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What is the answer to 7n-2(n+5)< 3n-16

Answers

7n-2(n+5)< 3n-16  / -3n-16
7n-2(n+5)-3n+16<0
5n-3n-10+16<0
2n-10+16<0
2n+6<0 / -6
2n< -6  / :2
n< -6/2
n< -3
n
є(-∞:-3)
7n-2(n+5)< 3n-16
7n-2n+10<3n-16      Distribute the 2 into n+5   
5n+10<3n-16          Subtract like figures
5n-3n+10<3n-3n-1  Subtract 3n from each side. (You want the variable on ONE side.)
2n+10-10<-16-10     Isolate the variable. Negative plus negative= bigger negative.
2n/2< -26/2             Negative divided by positive= smaller negative. Divide by 2 to isolate.
n<-13

Share 56 pound in the ratio 1:3:4

Answers

(56)/(1+3+4)\n(56)/(8)\n7\n\n7*1=7\n7*3=21\n7*4=28\n7:21:28

7 : 21 : 28

What is the surface area of a sphere with the given dimension? Express your answer to nearest hundredth. Use 3.14 for pi. Radius = 5cm.

Answers

Surface area of a sphere can be calculated as:

Surface Area = 4πr²

r = 5cm
π = 3.14

Using the values we get:

Surface Area = 4(3.14)(5²) = 314 cm²

Thus, the surface area of the sphere is 314 cm²
Okay. The equation for a sphere's surface area is A = 4 * pi * r^2. Let's plug 5 in for r. 
4 \pi (5^2) = 4(3.14)*25 = 100 * 3.14 = 314
I got 314 cm^2 is the surface area, but it always helps to double check work! Hope this helps!

Which graph correctly solves the system of equations below?y = 2x2 − 3
y = −x2

one quadratic graph opening down and one quadratic graph opening up. They intersect at 1, negative 1 and negative 1, negative 1.

one quadratic graph opening up and one quadratic graph opening down. They intersect at 0, negative 3.

two quadratic graphs opening up. They intersect at 0, negative 3.

quadratic graph opening up and quadratic graph opening down. They intersect at 1, 2 and negative 1, 2

Answers

Answer:

one quadratic graph opening down and one quadratic graph opening up. They intersect at 1, negative 1 and negative 1, negative 1

i.e. they intersect at (1,-1) and (-1,-1)

Step-by-step explanation:

We are asked to find which graph correctly solves the system of quadratic equations:

y=2x^2-3

and y=-x^2

on solving the equation by the method of substitution i.e. on equating both the equations we get:

2x^2-3=-x^2\n\n2x^2+x^2=3\n\n3x^2=3\n\nx^2=1\n\nx=+1,x=-1

Now on putting the value of x in any of the equations we get the value of y as:

y=-1

Hence, the point of intersections of both the graph is:

(1,-1) and (-1,1).

Also the graph of the quadratic equation:

y=2x^2-3

opens upward.

and graph of the quadratic equation:

y=-x^2

opens downward.

Hello,

answer A is True, others are false


Which expression is a PRODUCT?A) 8(6 + 3)
B)
8
(6 + 3)
C) 5(2) + 2(6 x 3)
Eliminate
D) 5(2 + 3) - 4(8 + 1)

Answers

the answer is A thanks for asking

Answer:

thank you

Step-by-step explanation:

Sketch one cycle of the sine curve. y = -3 sin 4theta

Answers

Answer:

Step-by-step explanation:

We have been given a function:

y=-3sin4\theta

We will compare it with the genral equation which is:

y=asin bx+c

Where, a is amplitude and period of function is (2\pi)/(b)

In given equation a is -3 and b is 4

So, period of the given equation is:

(2\pi)/(4)=(\pi)/(2)

Yo can look at the graph in the attachment.

The a is the amplitude and the period of the function is (2\pi )/(b)

We have been given a function

y = -3 sin 4 \theta

What is the general form of sin wave?

y=asinbx+c

We will compare it with the general equation which is

Where a is amplitude and period of the function is (2\pi )/(b)

In the given equation a is -3 and b is 4

So, the period of the given equation is:

(2\pi )/(4) =(\pi )/(2)

You can look at the graph.

To learn more about the sin wave visit:

brainly.com/question/25699025

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