A positively charged rod is brought near one end of an uncharged metal bar. the end of the metal bar farthest from the charged rod will be charged

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Answer 1
Answer: The answer is (Positive.)
Answer 2
Answer: The answer is a possitive charge between them

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The space shuttle is descending through the earth's atmosphere. How is the mass of the shuttle affected?A. It will remain constant. B. It will increase with descent. C. It will decrease with descent.
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Make a island with all renewable energy soursws and how it works and about it but at year 9 level​

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Answer:

How are we expected to make an island

NEED ASAP PLEASE !! Billy drops a water balloon from the roof of his house. Since the balloon began with an original velocity of zero, how far above ground was the balloon dropped if it took 2.5 seconds to hit the ground?

A. 30.6 m
B. 122.5 m
C. 12.3 m
D. 49.0 m

Answers

Answer: The correct answer is option (A).

Explanation:

Initial velocity of the balloon = 0 m/s

let the distance covered by the balloon from roof to the ground= h

Time taken by the balloon to reach the ground = t = 2.5 seconds

Acceleration due to  gravity = g =9.8 m/s^2

Using confuse equation of the motion:

h=ut+(1)/(2)gt^2

h=0 m/s* 2.5 s+(1)/(2)*9.8 m/s^2* (2.5 s)^2=30.625 m\approx 30.6 m

Hence, the correct answer is option (A).

The balloon was 30.65 meters above ground.

ANSWER: A

In a series circuit containing two unequal resistors, higher power is developed in the

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In a series circuit, the current that passes through both resistors is equal. What determines the power in that element would be the value of the resistance. In terms of current and resistance, power would be equal to the square of current multiplied by the resistance. So having a higher value of resistance would result in higher power.

Which of the following would you describe as a change in state?A) melting ice
B) burning paper
C) film being exposed to light
D) a piece of paper being cut in half

Answers

Melting ice is a change in state. (A)
A. Melting ice, because it is changing water from its solid state (ice) to its liquid state.

The flywheel of a steam engine runs with a constant angular velocity of 140 rev/min. When steam is shut off, the friction of the bearings and of the air stops the wheel in 1.9 h. (a) What is the constant angular acceleration, in revolutions per minute-squared, of the wheel during the slowdown? (b) How many revolutions does the wheel make before stopping? (c) At the instant the flywheel is turning at 70.0 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 40 cm from the axis of rotation? (d) What is the magnitude of the net linear acceleration of the particle in (c)?

Answers

Answer:

A) α = -1.228 rev/min²

B) 7980 revolutions

C) α_t = -8.57 x 10^(-4) m/s²

D) α = 21.5 m/s²

Explanation:

A) Using first equation of motion, we have;

ω = ω_o + αt

Where,

ω_o is initial angular velocity

α is angular acceleration

t is time the flywheel take to slow down to rest.

We are given, ω_o = 140 rev/min ; t = 1.9 hours = 1.9 x 60 seconds = 114 s ; ω = 0 rev/min

Thus,

0 = 140 + 114α

α = -140/114

α = -1.228 rev/min²

B) the number of revolutions would be given by the equation of motion;

S = (ω_o)t + (1/2)αt²

S = 140(114) - (1/2)(1.228)(114)²

S ≈ 7980 revolutions

C) we want to find tangential component of the velocity with r = 40cm = 0.4m

We will need to convert the angular acceleration to rad/s²

Thus,

α = -1.228 x (2π/60²) = - 0.0021433 rad/s²

Now, formula for tangential acceleration is;

α_t = α x r

α_t = - 0.0021433 x 0.4

α_t = -8.57 x 10^(-4) m/s²

D) we are told that the angular velocity is now 70 rev/min.

Let's convert it to rad/s;

ω = 70 x (2π/60) = 7.33 rad/s

So, radial angular acceleration is;

α_r = ω²r = 7.33² x 0.4

α_r = 21.49 m/s²

Thus, magnitude of total linear acceleration is;

α = √((α_t)² + (α_r)²)

α = √((-8.57 x 10^(-4))² + (21.49)²)

α = √461.82

α = 21.5 m/s²

In a closed system, the volume of a gas is not related to the volume of its enclosure.a. True
b. False

Answers


That's silly.  The volume of a gas is very intimately related
to the volume of its enclosure.  In fact, they're identical,
because a gas always expands to fill whatever you put it in.

The answer to your question would be FALSE. Gas takes up space and if it is in an enclosed area then it would directly relate to how much space/area there is for the gas to fill.