MATHEMATICS HIGH SCHOOL

B1 of a trapezoid in which Area = (48x+68) inch squared, Height = 8 in, B2 = (9x + 12) in.what I have so far is

48x +68 = 8 (B1 + 9x +12)

what do I do from there????????????????? the question is asking to solve for Base 1/ B1

Answers

Answer 1
Answer:

A=(1/2)(b1+b2)h =

=(48x+68)in² = (1/2)( b1+(9x+12))8

=b1= 3x+5

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PLEASE HELP ASAP AND GIVE A REAL ANSWERDifferent sizes of string needs to be cut to go around various shapes. All of the following sizes are in inches
2 44 16
(a) Without using your calculator, approximate the decimal equivalent of each number to the nearest
tenth
(b) Order the string sizes from least to greatest

Answers

3.1, 1.4, 8.0, 4.0

1.4, 3.1, 4.0, 8.0

10+6x = 15+9x-3xis this one solution, no solution, or multiple solution if one of 2 please tell me what is x

Answers

Simplifying
10 + 6x = 15 + 9x + -3x

Combine like terms: 9x + -3x = 6x
10 + 6x = 15 + 6x

Add '-6x' to each side of the equation.
10 + 6x + -6x = 15 + 6x + -6x

Combine like terms: 6x + -6x = 0
10 + 0 = 15 + 6x + -6x
10 = 15 + 6x + -6x

Combine like terms: 6x + -6x = 0
10 = 15 + 0
10 = 15

Solving
10 = 15

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

Answer:

No solution

Step-by-step explanation:

Let's solve this equation to see if there are any solutions.

First we need to simplify it;

10 + 6x = 15 + 9x - 3x

Combine like terms:

6x - 9x + 3x = 15 - 10

0x = 5

0 = 5

Zero cannot be equal to 5, so there is no solution

The length of a rectangle is twice the width. The perimeter of the rectangle is 24 feet. What is the length of the rectangle? Let x = the width of the rectangle. Which let statement would you use for the length?

Answers

A) L = 2*W
B) 2*L + 2*W = 24
Substituting A into B
2*2*W + 2*W = 24
6W = 24
W=4
L=8

PLEASE HELP, DUE AT MIDNIGHT >>>>>

Answers

Answer:

BELOW

Step-by-step explanation:

7.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-8,\:-11\right),\:\left(x_2,\:y_2\right)=\left(17,\:4\right)\n\nm=(4-\left(-11\right))/(17-\left(-8\right))\n\nm = (4+11)/(17+8)= (15)/(25) \n\mathrm{Refine}\n\nm=(3)/(5)

8.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(10,\:-15\right),\:\left(x_2,\:y_2\right)=\left(13,\:-17\right)\n\nm=(-17-\left(-15\right))/(13-10)\n\nm = (-17+15)/(13-10)\n \nm = (-2)/(3)\n \nSimplify\nm=-(2)/(3)

9.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(5,\:-7\right)\n\nm=(-7-\left(-7\right))/(5-\left(-6\right))\n\nm = (-7+7)/(5+6)\n \nm = (0)/(11)\n \nSimplify\nm=0

10.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-4,\:-3\right),\:\left(x_2,\:y_2\right)=\left(2,\:-9\right)\n\nm=(-9-\left(-3\right))/(2-\left(-4\right))\n\nm = (-9+3)/(2+4)\n \nm = (-6)/(6) \n\nSimplify\nm =-1

11.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\mathrm{When\:}y_1\ne \:y_2\mathrm{\:and\:}\:x_1=x_2\mathrm{\:the\:slope\:is\:}\infty \n\nm = \infty

12.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-5,\:3\right),\:\left(x_2,\:y_2\right)=\left(19,\:-6\right)\n\nm=(-6-3)/(19-\left(-5\right))\n\nm = (-6-3)/(19+5)\n \nm = (-9)/(24)\n \nSimplify\nm=-(3)/(8)

13.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-7,\:-12\right),\:\left(x_2,\:y_2\right)=\left(1,\:-16\right)\n\nm=(-16-\left(-12\right))/(1-\left(-7\right))\n\nm = (-16+12)/(1+7) \n\nm = (-4)/(8) \n\nSimplify\nm=-(1)/(2)

14.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(-18,\:0\right),\:\left(x_2,\:y_2\right)=\left(-13,\:1\right)\n\nm=(1-0)/(-13-\left(-18\right))\n\nm = (1-0)/(-13+18)\n \nm = (1)/(5) \n

15.

\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)\n\n\left(x_1,\:y_1\right)=\left(1,\:-11\right),\:\left(x_2,\:y_2\right)=\left(-2,\:-4\right)\n\nm=(-4-\left(-11\right))/(-2-1)\n\nm = (-4+11)/(-2-1)\n \nm = (7)/(-3) \n\nSimplify\nm=-(7)/(3)

Which is the equation of the linear model?A.y = 2.25x + 0.75

B.y = 0.75x + 2.25

C.y = 1.3x + 2.7

D.y = 0.75x + 3

Answers

The answer is B. y =  0.75 + 2.25. because i've done this assement.

A bag had 3 pink marbles and 4 purple marbles find the probability of selecting 3 pink marbles without replacement

Answers

There are 7 marbles in the bag.
The probability of drawing a  pink one is (3/7) .

Then you have 1 pink one, and there are 6 marbles in the bag.
The probability of drawing a pink one is (2/6) .

Then you have 2 pink ones, and there are 5 marbles in the bag.
The probability of drawing a pink one is (1/5) .

The probability of all 3 draws being successful is

           (3/7) (2/6) (1/5)  =  6/210  =  1/35  =  about  2.86%  (rounded)
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