Calculate the Energy (E) in joules for that wavelength and record it in the table below. Remember that E = HF, where h the Planck constant (6.6 10^-34 js)

Answers

Answer 1

Answer:
In that formula for Energy, 'F' is the frequency of the photon.
But Frequency = (speed)/(wavelength), so we can write the
Energy formula as
   E = h c / (wavelength) .

So the energy, in joules, of a photon with that wavelength, is . . .

   E = (6.6 x 10⁻³⁴) x (3 x10⁸) / (that wavelength)

      = (1.989 x 10⁻²⁵) / (that wavelength, in meters) .

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Which process produces the energy radiated by the star when it becomes a main sequence star?

Answers

The process that produces the energy radiated by stars is nuclear fusion in the core.
For a star on the main sequence, it's the fusion of hydrogen nuclei into helium.

An observer notes that the pitch of a sound is becoming progressively lower. The observer can conclude that the sound is moving

Answers

He can conclude that the source of the sound is moving away from him and that its speed is increasing.

The source of the sound is moving away from the receiver.

A 1.00 l sample of a gas at 25.0◦c and 1.00 atm contains 50.0 % helium and 50.0 % neon by mass. what is the partial pressure of the neon. express your answer in atmospheres.

Answers

V = Volume of sample of gas = 1.00 L = 0.001 m³

T = temperature of the gas = 25.0 ⁰C = 25 + 273 = 298 K

P = pressure = 1.00 atm = 101325 Pa

n = number of moles of gas

using ideal gas equation

PV = n RT

101325 (0.001) = n (8.314) (298)

n = 0.041

n₁ = number of moles of helium

n₂ = number of moles of neon

m₁ = mass of helium = n₁ (4) = 4 n₁

m₂ = mass of neon = n₂ (20.2) = 20.2 n₂

given that :

m₁ = m₂

4 n₁ = 20.2 n₂

n₁ = 5.05 n₂

also

n₁ + n₂ = n

5.05 n₂ + n₂ = 0.041

n₂ = 0.0068

mole fraction of neon is given as

mole fraction = n₂ /n = 0.0068/0.041 = 0.166

P₂ = partial pressure of neon = (mole fraction) P

P₂ = (0.166) (1)

P₂ = 0.166 atm

The partial pressure of the neon is 0.16 atm.

Explanation:

A 1.00 l sample of a gas at 25.0◦c and 1.00 atm contains 50.0 % helium and 50.0 % neon by mass. what is the partial pressure of the neon. express your answer in atmospheres.

The partial pressure is the notional pressure of constituent gas if it is occupied alone by the entire volume of the original mixture at the same temperature.

50.0 % helium and 50.0 % neon by mass.

$P = 1 atm$

Mass of the gases = $M$

$Moles of helium = (0.5M)/(4 g/mol)\nMoles of neon = (0.5M)/(20 g/mol)$

By using ideal gas equation we get:

$PV=nRT\nn=(PV)/(RT)=(1.00 L* 1.00 atm)/(0.0820 L atm/mol K* 298 K)=0.0409 mol$

where $n =$ total number of moles of gases

$0.0409 mol=(0.5M)/(4 g/mol)+(0.5M)/(20 g/mol)$

$M = 0.2728 g$

Then we can find the mass and mole of gases

The gas molar volume is the volume of one mole of the gas at a given temperature and pressure.

Mass of helium gas = $(0.2728g)/(2)=0.1364 g$

Moles of helium gas $=n_1=(0.1364 g)/(4 g/mol)=0.0341 mole$

Mass of neon gas $= (0.2728g)/(2)=0.1364 g$

Moles of neon gas $= n_2=(0.1364 g)/(20 g/mol)=0.00682mole$

Partial pressure of the neon gas: $P* \chi_2=P* (n_2)/(n_1+n_2)=1 atm* (0.00682)/(0.00682+0.0341)=0.16 atm$

Therefore the partial pressure of the neon gas is 0.16 atm.

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an input force of 50 Newtons is applied through a distance of 10 meters to machine with mechanical advantage of 3. If the work output for the machine is 450 newton x meters and this work is applied through a distnace of 3 meters, what is the output force of the machine

Answers

The output of the machine is

(output work) = (output force) x (distance)

450 N-m = (output force) x (3 meters)

Divide each side
by 3 meters: Output force = (450 N-m) / (3 m)

= 150 newtons .

With all the information given about the output work, we don't need
to know anything about the input work, or even the fact that we're
dealing with a machine.

It's comforting, though, to look back and notice that the output work
(450 N-m) is not more than the input work (500 N-m). So everything
is nice and hunky-dory.
___________________________________

Well, my goodness !
I didn't even need to go through all of that.

Given:

-- The input force to the machine is 50 newtons.

-- The mechanical advantage of the machine is 3 .

That right there tells us that

-- The output force of the machine is 150 newtons.

We don't need any of the other given information.

Which state of matter contains particles that move slightly in a fixed posistion

Answers

Solid moves slightly in a fixed position

Answer:

soliddddd

Explanation:

On a highway, a car is driven 80. kilometersduring the first 1.00 hour of travel,
50. kilometers during the next 0.50 hour, and
40. kilometers in the final 0.50 hour. What is the
car’s average speed for the entire trip?
(1) 45 km/h (3) 85 km/h
(2) 60. km/h (4) 170 km/h

Answers

The average speed of the car for the entire trip can be calculate by using:

$v=(S)/(t)$

where S is the total distance covered by the car, and t is the total time taken.

The total distance travelled by the car is:

$S=80 km+50 km+40 km=170 km$

while the total time taken is:

$t=1.00 h+0.50 h+0.50 h=2.00 h$

so, the average speed of the car is:

$v=(S)/(t)=(170 km)/(2.00 h)=85 km/h$

so, the correct answer is (3) 85 km/h.

The average speed of the car for entire trip is $\boxed{85\text{ km/h}}$ .

Further Explanation:

Speed is the measure of a quantity of an object the tells how fast the object is moving in the other words we can define the speed that it is the distance covered by an body divided by the time taken to cover that distance. It is a quantity with only magnitude so it is a scalar quantity.

The average speed is defined as the sum of all the distance traveled by the body divided by the sum of time taken to travel that distance.

Given:

The distance travel by the car is $80\text{ km}$ for $1.00\text{ hours}$ .

The distance travel by the car is $50\text{ km}$ for $0.50\text{ hours}$ .

The distance travel by the car is $40\text{ km}$ for .

$0.50\text{ hours}$ .

Concept:

The expression for the average can be written as:

S = $\frac{{{\text{sum of distances }}}}{{{\text{sum of time}}}}$ …… (1)

The distance travel by the car is $80\text{ km}$ for $1.00\text{ hours}$ , distance travel by the car is $50\text{ km}$ for $0.50\text{ hours}$ and distance travel by the car is $40\text{ km}$ for $0.50\text{ hours}$ .

The sum of the distance is:

$\begin{aligned}D&=80{\text{ km}}+{\text{50 km}}+40{\text{ km}}\n&=170{\text{ km}}\end{aligned}$

The sum of time taken to travel the distance is:

$\begin{aligned}t&=1.00{\text{ h}} + 0.50{\text{ h}} + 0.50{\text{ h}}\n&=2.00{\text{ h}}\end{aligned}$

Substitute $170\text{ km}$ for total distance and $2.00\text{ h}$ for total time in equation (1).

$\begin{aligned}S&=\frac{{{\text{170 km}}}}{{2.00{\text{ h}}}}\n&=85{\text{ km/h}}\end{aligned}$

Therefore, the average speed of the car for entire trip is $\boxed{85\text{ km/h}}$ .

Learn more:

1. Find the net force. https://brainly.in/question/8668644

2. Find the velocity. https://brainly.in/question/4502003

3. Calculate average speed brainly.com/question/11597590

Answer Details:

Grade: Middle school

Subject: Physics

Chapter: Kinematics

Keywords:

Highway, car, driven, 80 km, 1.00 hour, 1.00 hr, 1.00 h, 50 km, 0.50 hour, 0.50 hr, 0.50 h, 50 km, average speed, entire, trip, 85 km/hr.

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Calculate the Energy (E) in joules for that wavelength and record it in the table below. Remember that E = HF, where h the Planck constant (6.6 *10^-34 j*s)

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Calculate the Energy (E) in joules for that wavelength and record it in the table below. Remember that E = HF, where h the Planck constant (6.6 10^-34 js)