Imagine two billiard balls on a pool table. Ball A has a mass of 2 kilograms and ball B has a mass of 3 kilograms. The initial velocity of ball A is 9 meters per second to the right, and the initial velocity of the ball B is 6 meters per second to the left. The final velocity of ball A is 9 meters per second to the left, while the final velocity of ball B is 6 meters per second to the right. 1. Explain what happens to each ball after the collision. Why do you think this occurs? Which of Newton’s laws does this represent?

2. What can you say about the total momentum before and after the collision?

3. What do you think would happen to the velocity of each ball after the collision if the masses and initial velocities of each ball were the same?

4. The mass of ball A is 10 kilograms and the mass of ball B is 5 kilograms. If the initial velocity is set to 3 meters per second for each ball, what is the final velocity of ball B if the final velocity of ball A is 2 meters per second? Use the elastic collision equation to find the final velocity of ball B. Assume ball A initially moves from right to left and ball B moves in the opposite direction. Identify each mass, velocity, and unknown. Show your work, including units, and indicate the direction of ball B in your answer.

5. If the mass of each ball were the same, but the velocity of ball A were twice as much as ball B, what do you think would happen to the final velocity of each ball after the collision? To answer this question, create a hypothesis in the form of an if-then statement. The “if” is the independent variable, or the thing that is being changed. The “then” is the dependent variable, or what you will measure as the outcome.
(Please show your work if you can)

Answers

Answer 1

Answer: 1. After the collision, their velocities have switched. This is Newton's third law of motion.

2. The total momentum is conserved.

3. The same thing would happen if the collision is totally elastic.

For 4 and 5.
Using the conservation of momentum equation
m1v1 + m2v2 = m1'v1' + m2'v2'

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Answer:

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Answers

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I hope this helps :)

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Answers

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Answers

The right answer for the question that is being asked and shown above is that: "wave B as a louder and higher pitched sound than wave A." Compare the sounds produce by wave A and wave B. The human ear would hear wave B as a louder and higher pitched sound than wave A.

Answer:

It's A

Explanation:

The human ear would hear wave A as a louder sound than wave B. Wave A has a greater amplitude than wave B. That is perceived as a louder sound. Wave B has a higher frequency; that would be perceived as a higher pitch.

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Answers

In order to solve this problem, there are two equations that you need to know to solve this problem and pretty much all of kinematics. The first is that d=0.5at^2 (d=vertical distance, a=acceleration due to gravity and t=time). The second is vf-vi=at (vf=final velocity, vi=initial velocity, a=acceleration due to gravity, t=time). So to find the time that the ball traveled, isolate the t-variable from the d=0.5at^2. Isolate the t and the equation now becomes $√((2d)/a)$ . Solving the equation where d=8 and a=9.8 makes the time $√((2*8)/9.8)$ =1.355 seconds. With the second equation, the vi=0 m/s, the vf is unknown, a=9.8 m/s^2 and t=1.355 sec. Substitute all these values into the equation vf-vi=at, this makes it vf-0=9.8(1.355). This means that the vf=13.28 m/s.

Answer:

The answer is 12.5 m/s

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or v = the square root of 2 x (9.8 x 8)

Explanation:

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