answer: 3/1
Step-by-step explanation:
This is like a puzzle, and each part tells you something. The first statement tells us that x is a negative number and y is a positive number. The next statement, x + y , is what we need to know. The first absolute value gives us x. Solve for the absolute value, that is, what is inside can be either negative or positive so either x-9 = 12 or x - 9 = -12. Solve those for x = 21 or x = -3. We know that x is negative from that first statement, , so x is -3. Do the same with the other absolute value to solve for y, then add the two together to get your final answer. hope this helps a bit!
(B)3.585
(C)6.230
(D)8.535
(E)11.230
Answer:
E
Step-by-step explanation:
Since the given expression is an elliptic integral, it's not easy to find F(x) explicitly. However, if we use a linear approximation, we can try to estimate F(3), though it won't be too close, since 3 is not very close to 1.
At the point (1,5) the slope of the tangent line is F'(1) =
So, using that line,
F(3) = F(1) + F'(1)(3-1) = 5+2 = 7.828
Well, that didn't work out too well.
So, let's pull out our handy integral calculator, and we find that
But, we know that F(1) = 5. So we need to add C = 3.889
Now, integrating again,
Oops. I messed up the limits, but you get the idea.
Firstly, we will draw figure
now, we will draw a altitude from B to DC that divides trapezium into rectangle and right triangle
because of opposite sides of rectangle ABMD are congruent
so,
DM=AB=9
CM=CD-DM
CM=18-9
CM=9
now, we can find BM by using Pythagoras theorem
now, we can plug values
we get
now, we can find area of trapezium
now, we can plug values
and we get
so, area of of the trapezoid is ..........Answer
Hello,
All the numbers must begin with 6.
There are still 2,3,4,5 digits : 4 possibilities.
4!=4*3*2*1=24
The first is 62345 and the last 65432.
To find the number of odd numbers greater than 60000 that can be formed using the given numbers with each digit used only once, you can determine the number of possibilities for each digit and multiply them together. The answer is 96.
To find the number of odd numbers greater than 60000 that can be formed using the numbers 2, 3, 4, 5, and 6 with each digit used only once, we need to consider the possible arrangements of these digits. First, we can determine the number of possibilities for the leftmost digit, which must be either 3, 4, 5, or 6. Next, we can determine the number of possibilities for the remaining four digits, which can be arranged in 4! (4 factorial) ways. Multiplying these two values gives us the total number of odd numbers greater than 60000 that can be formed using these digits with each digit used only once.
Thus, the number of odd numbers greater than 60000 that can be formed using the numbers 2, 3, 4, 5, and 6 with each digit used only once is 4 * 4! = 4 * 4 * 3 * 2 * 1 = 96.
#SPJ2
Hey,here is the answer to ur question..!
1.BD=AE (given)
2. Ci Is the midpoint of BD and AE (given)
3. AC=EC (Cis the midpoint Of AE)
4. BC=DC (midpoint theorem)
5.angle ACB and angle ECD are vertical angles ( definition of vertical angles)
6. angle ACB=angle ECD (vertical angle theorem)
7.triangle ABC Is congruent to triangle EDC ( SSS criterion rule)
Hope this helps u....!!!