$25;300%increse percent change

Answers

Answer 1
Answer:


well and 300% increase means you multiply by 3 and then add the original number


in this case 300% of 25 is 75 and its an increase so 25+75=100

the answer is 100


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Solve for x. Round to the nearest tenth, if necessary.

Answers

The value of the variable 'x' using the cosine formula will be 9.4 units.

What is a right-angle triangle?

It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometry function.

Trigonometric functions examine the interaction between the dimensions and angles of a triangular form.

The value of 'x' is given by the cosine of the angle ∠VWU. And the cosine of an angle is the ratio of the base and hypotenuse of the right-angle triangle. Then we have

cos 32° = 8 / x

x = 9.4

The value of the variable 'x' using the cosine formula will be 9.4 units.

More about the right-angle triangle link is given below.

brainly.com/question/3770177

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Answer:

9.4

Step-by-step explanation:

cos 32° = 8/x

x = 8/ cos 32°

= 8/ 0.8480

= 9.4

Write an equation of a circle whose center is (-3,2) and whose diameter is 10

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The\ equation\ of\ a\ circle:(x-a)^2+(y-b)^2=r^2\n\n(a;\ b)-the\ coordinates\ of\ the\ cener;\ r-the\ radius\n-------------------------------\nThe\ center\ (-3;\ 2)\to a=-3;\ b=2\na\ diameter\ d=2r\ therefore\ r=(1)/(2)d\to r=(1)/(2)\cdot10=5\n\nAnswer:\n\boxed{(x-(-3))^2+(y-2)^2=5^2}\to\boxed{(x+3)^2+(y-2)^2=25}
(x-x_1)^2+(y-y_1)^2=r^2\n(x_1,y_1) - \text{ center}\n\nr=\frac{\text{ diameter}}{2}=(10)/(2)=5\n\n(x-(-3))^2+(y-2)^2=5^2\n\boxed{(x+3)^2+(y-2)^2=25}

How do I multiply percent

Answers

turn the percent to a decimal, and then multiply

What is the ratio of 5 hours to 100 minutes

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for this question you should know that 5 hours is equal to 300 minutes so the ratio of 300 minutes to 100 minutes is 300/100 which is equal to 3/1 or 3 :)))
i hope this is helpful
have a nice day 
first 5x60=300
therefore...   300:100
300/50=6   and    100/50=2
6:2
therefore is 3/1

I need an even function with an odd degree.

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Try [ y = |x cubed| ]. Or even. [ y = |x| ] for that matter.

Containing the points (-1,2) and (5,-4)

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the equation conatining the points would be
y=mx+b, m=slope b=y inercept
find slope

slope=(y1-y2)/(x1-x2)=(2-(-4))/(-1-5)=(6)/(-6)=-1

slope is -1
y=-1x+b

input one of the points and solve for b
2=-(-1)+b
2=1+b
subtract 1 form both sides
1=b

answer=
y=-1x+1