Compression leads to the folding of the crust, which results in the formation of __________.

Answers

Answer 1
Answer: anticlines and synclines

Related Questions

Cellulose is a major component of the _____.
In the practice of ________, scabs from smallpox victims were used to immunize susceptible individuals against smallpox.
Convert the volume of CO2 you measured in the glucose reaction to moles of CO2 using the Ideal Gas Law to solve for n. Assume P is 1 atm. n = PV/RTwhere P is the atmospheric pressure in the lab, V is the volume in liters of CO2, n is the number of moles of CO2, R is the gas constant 0.082 L-atm/mole-Kelvin, and T is the temperature in Kelvin. Convert the gas volume to L by dividing the volume in mL by 1000.
Meiosis allows for the reshuffling of maternally and paternally-inherited alleles between different genes, thus allowing for high genetic diversity in gamete genotypes, and thus offspring produced. Which of the following correctly relates a mechanism of reshuffling alleles of different genes with respect to each other with the location of genes on chromosomes? recombination reshuffles alleles of two genes that lie on the different chromosome types, whereas independent assortment reshuffles alleles of two genes that lie on the same chromosome type. recombination reshuffles alleles of two genes that lie on the same chromosome type, whereas independent assortment reshuffles alleles of two genes that lie on different chromosome types.
Building material examination

List planets that have rings.

Answers

Answer: Jupiter, Saturn, Uranus, and Neptune

Explanation:

Why can’t bears , tigers and lion live together

Answers

Because they would kill each other

Answer:

Bears, lions, and tigers all are predators that have similar hunting habits such as medium to large prey. Because of this, if they were living in the save environment, they would be competing for food and space. This would cause them to attack and kill off each other until one remained. That or the other two species would be driven out of the area.

Explanation:

2×4×45×5+10-8 lol? hehhehehehehehehehehe bruh i just wanna change my question so i put this

Answers

Answer:

1802

Explanation:

(8)(45)(5)+10−8

(360)(5)+10−8

1800+10−8

1810−8

1802

anything else!!!!

Each strand of a DNA molecule contains nitrogenous bases that pair with other nitrogenous bases in very specific ways. A segment of a DNA strand is shown. 3’ GATCGATC 5’

Which complementary DNA strand pairs correctly with the strand above?

A. 5’ CTAGCTAG 3’
B. 5’ GATCGATC 3’
C. 5’ CUAGCUAG 3’
D. 5’ CATCGATC 3’

Answers

Each base pair forms a "rung of the DNA ladder" by joining two complementary DNA nucleotide bases. Two linked strands of DNA form a double helix, which is a structure that resembles a twisted ladder.

What is complementary base pairing in DNA molecule?

Because they are complementary base pairs, adenine binds to thymine while guanine attaches to cytosine. The complimentary bases may unite to form a bond.

This aids in holding the DNA molecule's two antiparallel strands together to form the helix. The complimentary base pairing rule refers to this.

Cytosine pairs with guanine, while adenine pairs with thymine. The two strands are so complimentary to one another.

For instance, a complementary DNA strand will have the nucleotidesequence 5' CTAGCTAG 3' for a DNA strand with the nucleotide sequence 3' GATCGATC 5'.

Therefore, According to this rule, nucleotides A and T and bases G and C are always equally abundant in DNA.

Learn more about base pairing here:

brainly.com/question/14641006

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A. 5’ CTAGCTAG 3’ because it’s asking for the complementary DNA not RNA

Why would a grassland ecosystem have more primary consumers than a forest ecosystem

Answers

Answer:

Grass is easier for herbivores to digest.

The energy in trees is less available to herbivores

Explanation:

Answer:

grass is easier for herbivores to digest.

Explanation:

Suppose experiment was performed with the monosaccharide fructose instead of glucose. A beaker was filled with 30 ml of DNP + 15 mM fructose, and an everted intestinal sac was filled with Mammalian Ringers+ 10 mM fructose. Predict the final concentration of fructose inside the sac after 1 hr incubation at 37°C.

Answers

Answer:

greater than 10 mM.

Explanation:

This question deals with the transport of monosaccharide into the everted sacs of the intestine. And in order to be able to solve this question efficiently one must have prerequisite idea on the transport protein for the Sodium ion process of absorption. Also, one must know the structure of the epithelial.

What happens during the experiment is that there will be an absorption of the fructose, the Chloride ion and the Sodium ion and this absorption will lead to the production of osmotic gradient. Therefore,as the osmotic is produced, the fructose will be transported into the sac through diffusion and thus increasing the concentration of fructose.