Perform the following computations. retail price of steel-belted radial tire = $89.50 discount offered = 10% federal tax = 12% local sales tax = 5% selling price = _____. 66.86 94.24 95.76 112.15

Answers

Answer 1

Answer: For the answer to the question above
Retail price of steel-belted radial tire = $89.50
Discount offered = 10% = $8.95
Value before federal tax = $89.50 - $8.95 = $80.55
Federal tax = 12%=$80.55(0.12) =$9.67
Local sales tax = 5% =$80.55(0.05)=$4.03

Selling price = $80.55 +$9.67+$4.03 =$94.25
I hope my answer helped you. Feel free to ask more questions. Have a nice day!

Answer 2

Answer:

Answer:

94.25

Step-by-step explanation:

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Answers

The second answer on the list is the correct one.

What is the value of h when the function is converted to vertex form?
g(x) = x^2 – 6x + 14

Answers

Hello,

g(x)=x²-6x+14=x²-2*3x+9+14-9=(x-3)²+5
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If f(x) = 6 – 5x and g(x) = 4x – 1, evaluate f(x) – g(x) for x = –2. A. –11 B. 7 C. 9 D. 25

Answers

Answer:

D. 25

Step-by-step explanation:

f(x) = 6 – 5x and g(x) = 4x – 1

We want to subtract.

f(x) -g(x)= 6 – 5x -( 4x – 1)

Distribute the minus sign

6 – 5x - 4x + 1

I line them up vertically

– 5x +6

- 4x + 1

-------------------

-9x +7

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What is the excluded value of x for the expression 1/x-6? A.) x = –6
B.) x = –1
C.) x = 1
D.) x = 6

Answers

Answer:

Option (d) is correct.

The excluded value of x for the given expression $(1)/(x-6)$ is 6.

Step-by-step explanation:

Given : Expression $(1)/(x-6)$

We have to find the excluded value of x for the given expression $(1)/(x-6)$ .

Consider the given expression $(1)/(x-6)$

Since, when x = 6 then the value of denominator becomes 0 and also, the expression $(1)/(6-6)$ becomes $(1)/(0)$ , which makes the expression not defined.

Thus, The excluded value of x for the given expression $(1)/(x-6)$ is 6.

the excluded value of x for the expression 1/x-6 is
D.) x = 6

Find 2 consecutive odd numbers given that difference between their resiprocal is 2/63

Answers

consecutive odd numbers are 2n+1, 2n+3

difference of reciprocals
1/(2n+1) - 1/(2n+3) = 2/63
((2n+3) - (2n+3))/(2n+1)(2n+3) =2/63
2/(4n^2 + 8n +3) =2/63
4n^2 + 8n +3 = 63
4n^2 + 8n -60 = 0
n^2 + 2n - 15 = 0
(n + 5)(n - 3) = 0
n = 3 (only positive)
numbers are 2(3)+1=7 and 9

Those odd numbers are nine and seven.

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