Josh walks 18 dogs each week. Today, he is walking 1/3 of the dogs. How many dogs is he walking today?

Answers

Answer 1

Answer: 18*(1/3) (or one third of eighteen) = 6 dogs

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Write two irrational numbers between 1 and 2

Answers

$(\pi)/(2),√(\pi)$

$Answer : √(2)$ and $√(3)$

Ashlynd's backpack has a mass of 30,000 grams. What is the mass of ashlynd's backpack on kilograms?

Answers

1,000 grams = 1 kilogram
2,000 grams = 2 kilograms
3,000 grams = 3 kilograms
4,000 grams = 4 kilograms
5,000 grams = 5 kilograms
.
.
10,000 grams = 10 kilograms
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20,000 grams = 20 kilograms
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30,000 grams = 30 kilograms

the ratio of the number of apples to the number of oranges is 4:6. The ratio of the number of oranges to the number of pears is 8:1. How many apples, Oranges and pears are there if there are 172 fruits.

Answers

The answer is 64 apples, 96 oranges, and 12 pears.

Let's represent the fruit as following:
a - the number of apples,
o - the number of oranges,
p - the number of pears.

$a:o=4:6$
⇒ $(a)/(o)= (4)/(6)$
⇒ $a= (4)/(6)o$

$o:p=8:1$
⇒ $(o)/(p)= (8)/(1)$
⇒ $o= 8p$

Therefore:
$a= (4)/(6)*8p =16/3p$

Now, if $a+o+p=172$ , then:
$(16)/(3)p +8p+p=172$
$(16)/(3)p +9p172$

Since $9= (9)/(1) = (27)/(3)$ , 9p can be expressed as 27/3p:
$(16)/(3)p+ (27)/(3)p=172$
$(43)/(3)p =172$
⇒ $p =172* (3)/(43)$
⇒ p = 12
There are 12 pears.

Since o = 8p, o = 96:
o = 8 × 12 = 96
There are 96 oranges.

Since $a= (16)/(3)p$ , a = 64:
$a= (16)/(3) *12=16*4=64$
There are 64 apples.

Therefore, there are 64 apples, 96 oranges, and 12 pears.

What’s 10% of 70 I really need the answer plz help!!!!!

Answers

10% of 70 is 7

hope this help

7%, sorry for late respond but hope it helps :)<3!

Find the value of 3/7 of 64

Answers

Answer:

27.4285714286

Step-by-step explanation:

You would divide 64 by 7 and multiply that by 3.

Please solve these coin problems:1) James bought 80 postage stamps for which he paid $18.40. Some were 1 cent stamps and some were 33 cent stamps.how many of each kind did he buy?

2) a postal clerk sold 75 stamps for $19.90. Some were 20 cent and some were 34 cent stamps. How many of each kind did he sell?

Answers

1)
Solving from system of equations:
x- amount of 1 cent stamps
y- amount of 33 cent stamps
$\left \{ {{1*x+33*y=18,40} \atop {x+y=80}} \right.\nx=80-y\n0,01*(80-y)+0,33y=18,40\n0,8-0,01y+0,33y=18,40\n0,32y=18,40-0,8\n0,32y=17,60 /:0,32\ny=55\nx=80-55=25$
2)
x- amount of 20 cent stamops
y-amount of 34 cent stamps
From system of equations:
$\left \{ {{0,2x+0,34y=19,90} \atop {x+y=75}} \right.\nx=75-y\n0,2(75-y)+0,34y=19,90\n 15-0,2y+0 ,34y=19,90\n-0,2y+0,34y=19,90-15\n0,14y=4,90/:0,14\n y=35\nx=75-35=40$

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