b. testes; fallopian tubes
c. vas deferens; ovaries
d. vas deferens; fallopian tubes
Answer:
The ________________ in males and the _____________________ in females are permanently blocked when an individual undergoes a sterilization procedure.
a. testes; ovaries
b. testes; fallopian tubes
c. vas deferens; ovaries
d. vas deferens; fallopian tubes
Explanation:
I believe the answer would be B. This would be because the Fallopian tubes I think are tied which then would help so the sperm cannot go up to the ovaries. We know that it is A or B because the first answer being tested is correct.
a. When crossing triply heterozygous flies (Aa Bb Cc), where each gene has one dominant allele and one recessive allele, the phenotypic ratios among the progeny would be 1:1. b. The genotype of the wild-type male can be deduced based on the phenotypic ratios observed in the crosses with the tester strains.
a. If you crossed triply heterozygous flies (Aa Bb Cc), where each gene has one dominant allele and one recessive allele, you can use the product rule to predict the phenotypic ratios among the progeny.
For each gene, the possible gametes are A and a, B and b, C and c. When you cross the triply heterozygous flies, you can determine the possible genotypes of the offspring:
Genotypes:
AA BB CC (wild type)
AA BB Cc (wild type)
AA Bb CC (wild type)
AA Bb Cc (wild type)
Aa BB CC (wild type)
Aa BB Cc (wild type)
Aa Bb CC (wild type)
Aa Bb Cc (wild type)
The phenotypic ratios can be determined by counting the number of wild-type (dominant phenotype) offspring and dividing it by the total number of offspring:
Wild-type progeny (AA BB CC, AA BB Cc, AA Bb CC, AA Bb Cc, Aa BB CC, Aa BB Cc, Aa Bb CC, Aa Bb Cc) = 8
Total number of progeny = 8 (since each possible genotype occurs once)
Phenotypic ratio: 8 wild-type : 8 total = 1:1
b. To determine the genotype of the wild-type male, we can deduce it based on the phenotypic ratios observed in the crosses with the tester strains.
In the cross with the tester strain AA bb cc, only 1/4 of the progeny are wild type. This means that the male being tested (wild-type male) must be heterozygous for the B and C genes (Aa Bb Cc) since the wild-type phenotype requires one dominant allele for each of the three genes.
In the crosses involving the other two tester strains (aa BB cc and aa bb CO), half of the progeny are wild type. This indicates that the wild-type male is homozygous for the A gene (AA Bb Cc) since the wild-type phenotype requires two dominant alleles for the A gene.
So, the genotype of the wild-type male is Aa BB Cc.
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Answer:
the genotype depends more on if its a boy or girl
Explanation: