Which bond is most polar? A) N -H
B) C -H
C) O -H
D) H -H
Can anyone explain this one?

Answers

Answer 1

Answer: A) N is more polar because of it electron negativity charge ex. N electron negativity charge is 3.0 and H is 2.1
B) C is more polar...electron negativity for C is 2.5 AND H is 2.1
C)O is more polar dues to it electron negativity charge being greater that hydrogen
D)H and H are both non polar because they cancel each other out due to the face the both share the electron negativity evenly

Answer 2

Answer: C .. ectronegativity values for each of the atoms but if you didn't know these you can just look at your periodic table and see where they are in relation to each other

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Yesterday we combined Hydrochloric Acid HCl with Sodium Hydroxide NaOH in a violent reaction that resulted in water H2O and common table salt NaCl. How many grams of hydrochloric acid should we use so we have exactly enough to react with 40g of sodium hydroxide? You'll need to write a chemical reaction, balance it, and then perform your calculation.

also how many grams of salt NaCl will be produced and how many grams of water H2O be produced?

Answers

HCl + NaOH ---> NaCl + H2O

1 mol HCl = 1 mol NaOH

mole HCl = 36.5 g // mole HaOH = 40 g

36.5 HCl is the answer.

mole NaCl = 58,5 g // mole H2O = 18g

HCl (36,5 g) ⇒ NaCl (58,5 g)
HCl (36,5 g) ⇒ H2O (18 g)

So, 58,5 g NaCl and 18 g H2O are the answer.

Reaction:
HCl + NaOH ---> NaCl + H2O

1 mole of HCl = 36,5 g
1 mole of NaOH = 40g

so, according to the reaction:
1 mol HCl = 1 mol NaOH
so, we need > 36,5 g HCl (hydrochloric acid)

answer: 36,5 g HCl (hydrochloric acid)
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
next question.

1 mole of NaCl = 58,5 g
1 mole of H2O = 18g

so, according to the reaction:
1 mole of HCl (36,5 g) ----------------- - 1 mole of NaCl (58,5 g)
(the same for NaOH)
i
1 mole of HCl (36,5 g) ------------------ 1 mole of H2O (18 g)
(the same for NaOH)

so, this reaction is stechiometric

answer: 58,5 g NaCl i 18g H2O

A.) Thermal Decomposition of 2.765 g NaHCO3 yields 1.234g of a solid Na2CO3 . Calculate the theoreticial yield and percent yield of Na2CO3.B) Thermal decomposition of 2.968 g of a mixture containing NaHCO3 lost 0.453 g . Calculate the percentage of NaHCO3 in this unknown mixture

Answers

Answer:

For A: The percent yield of sodium carbonate is 70.5 %

For B: The percent of sodium hydrogen carbonate in the unknown mixture is 15.26 %

Explanation:

For A:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of sodium hydrogen carbonate = 2.765 g

Molar mass of sodium hydrogen carbonate = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of sodium hydrogen carbonate}=(2.765g)/(84g/mol)=0.033mol$

The chemical equation for the thermal decomposition of sodium hydrogen carbonate follows:

$2NaHCO_3(s)\rightarrow Na_2CO_3(s)+CO_2(g)+H_2O(g)$

By Stoichiometry of the reaction:

2 moles of sodium hydrogen carbonate produces 1 mole of sodium carbonate

So, 0.033 moles of sodium hydrogen carbonate will produce = $(1)/(2)* 0.033=0.0165mol$ of sodium carbonate

Now, calculating the mass of sodium carbonate from equation 1, we get:

Molar mass of sodium carbonate = 106 g/mol

Moles of sodium carbonate = 0.0165 moles

Putting values in equation 1, we get:

$0.0165mol=\frac{\text{Mass of sodium carbonate}}{106g/mol}\n\n\text{Mass of sodium carbonate}=(0.0165mol* 106g/mol)=1.75g$

To calculate the percentage yield of sodium carbonate, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100$

Experimental yield of sodium carbonate = 1.234 g

Theoretical yield of sodium carbonate = 1.75 g

Putting values in above equation, we get:

$\%\text{ yield of sodium carbonate}=(1.234g)/(1.75g)* 100\n\n\% \text{yield of sodium carbonate}=70.5\%$

Hence, the percent yield of sodium carbonate is 70.5 %

For B:

To calculate the percentage composition of sodium hydrogen carbonate in mixture, we use the equation:

$\%\text{ composition of sodium hydrogen carbonate}=\frac{\text{Mass of sodium hydrogen carbonate}}{\text{Mass of mixture}}* 100$

Mass of mixture = 2.968 g

Mass of sodium hydrogen carbonate = 0.453 g

Putting values in above equation, we get:

$\%\text{ composition of sodium hydrogen carbonate}=(0.453g)/(2.968g)* 100=15.26\%$

Hence, the percent of sodium hydrogen carbonate in the unknown mixture is 15.26 %

2NaHCO3 -> Na2CO3 + H2O + CO2
2.765g NaHCO3/MM = moles NaHCO3
moles NaHCO3 x (1 mole Na2CO3 / 2 moles NaHCO3) x MM Na2CO3 = theoretical yield of Na2CO3

Percent yield is simply the actual yield/theoretical yield (x100 to put it into percentage).

MM = Molar mass (grams of substance per mol)

The physicals properties of a substance can be used to identify the substance, because_____. Select all that apply.at any given location, the physical properties of a substance do not change
when the substances are chemically reacted the physical properties remain the same
each substance has a unique set of physical properties
no two substances have any of the same properties

Answers

The answer is C because having a unique set of features sets the substance apart from another substance.

The following statements apply:

1. At any given location, the physical properties of a substance do not change.

2. Each substance has a unique set of physical properties.

Each substance usually has some characteristics that are peculiar to it and these characteristics can be used to identify them and separate them from other materials. Change of location does not affect the properties of substances, thus, the properties of oxygen that is found in America is the same as the one that is found in Nigeria.

Changing the pressure of a system has the highest effect on a substance in which phase?a. gas
b. solid
c. liquid
d. plasma

Answers

The best answer to the question presented above would be letter a. Changing the pressure of a system has the highest effect on a gaseous phase. Solids and liquids under pressure make little difference, while gas molecules have many behaviors due to change in pressure.

Ammonia is an important ingredient in many fertilizers. The main process by which ammonia is made is the Haber process. In this process, nitrogen gas and hydrogen gas are reacted to form ammonia at high temperatures. Which of the following most likely explains why this reaction is carried out at high temperature?Ammonia is unstable at room temperature.
High temperatures increase the activation energy of the reaction.
High temperatures make the gas molecules move more quickly.
The reaction becomes exothermic at high temperatures.

Answers

The best answer is "High temperatures increase the activation energy of the reaction."

The Haber process is an exothermic reaction at room temperature. This means that the reaction actually favors the reverse reaction, especially when the temperature is increased. So why increase the reaction temperature?

The reason for this is that nitrogen is a very stable element. Therefore, more energy is needed to overcome the slow rate of reaction. So the reaction temperature must be low enough to favor a forward reaction, but high enough to speed up the reaction.

this is wrong do not put this if your with FLVS

the correct answer is C i got 100% on it

In the combustion of hydrocarbon, carbon monoxide is formed. What has occured?

Answers

An incomplete combustion happened in the combustion of a hydrocarbon where carbon monoxide is produced. It happens when there is not enough oxygen to combust the hydrocarbon. The opposite is the complete combustion where CO2 and H2O is formed.

Answer: This is an incomplete combustion reaction.

Explanation:

Combustion reaction is defined as the reaction in which a hydrocarbon produces carbon dioxide gas and water molecule when reacted with oxygen gas. General equation for this reaction is:

$\text{Hydrocarbon}+O_2(g)\rightarrow CO_2(g)+H_2O(l)$

Incomplete combustion is also a reaction between oxygen and hydrocarbon in which the products obtained are carbon monoxide, water and carbon. This type of combustion happens when there is insufficient supply of oxygen gas. General equation for this reaction is:

$\text{Hydrocarbon}+O_2(g)\rightarrow CO(g)+H_2O(l)+C(s)$