MATHEMATICS HIGH SCHOOL

A car travels 120km at a certain speed. If the journey takes 2 1/2{Two and the half hours}, find the average speed{Let the speed be v km/h}

Answers

Answer 1

Answer:

Answer:

48 km/h

Step-by-step explanation:

Distance = 120 km

Time = 2½ h

Speed = ?

We know that

Speed = Distance/Speed

Let,

Speed = v km/h

=> v = 120/(2½)

=> v = 120/(5/2)

=> v = 120 × 2/5

=> v = 24 × 2

=> v = 48 km/h

Average speed is 48 km/h

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Sarah is twice as old as her youngest brother if the difference between their ages is 15 years how old is her youngest brother
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Find the dimensions of a rectangle whose perimeter is 26 meters and whose area is 40 square meters.

Divide. (4x^3+2x+1)÷(x+1)4x^2−4x+6+5/x+1

4x^2−4x+6−5/x+1

4x^2+4x−6−5/x+1

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Answers

$(4x^3+2x+1)/(x+1)=4x^2-4x+6-(5)/(x+1)$

Which expression gives the solutions of -5+2x^2=-6x

Answers

Answer:

The solutions are

$x1=(-6+2√(19))/(4)$

$x2=\frac{-6-2√(19)} {4}$

Step-by-step explanation:

we have

$-5+2x^(2) =-6x$

rewrite the quadratic equation

$2x^(2)+6x-5=0$

The formula to solve a quadratic equation of the form $ax^(2) +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}$

in this problem we have

$2x^(2)+6x-5=0$

$a=2\nb=6\nc=-5$

substitute in the formula

$x=\frac{-6(+/-)\sqrt{6^(2)-4(2)(-5)}} {2(2)}$

$x=\frac{-6(+/-)√(76)} {4}$

$x=\frac{-6(+/-)2√(19)} {4}$

$x1=(-6+2√(19))/(4)$

$x2=\frac{-6-2√(19)} {4}$

-5 + 2x² = -6x
rearrange the equation to the form ax² + bx + c = 0

=> 2x² + 6x - 5

use the quadratic formula to solve for the value(s) of x $-b ± \sqrt{ (b^(2) - 4ac)/(2a) }$

=> $-6 ± \sqrt{ (6^(2) - 4(2)(-5))/(2(2)) }$

=> $-6 ± \sqrt{ (36 - (-40))/(4) }$

=> $-6 ± \sqrt{ (76)/(4) }$

∴ x = $-6 + √( 19) }$ OR x = $-6 - √(19)$

x = - 1.64 ; x = - 10.36

How the hell do you find the range of a function by looking at a graph?

Answers

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis

Overall, the steps for algebraically finding the range of a function are:

Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).

Find the domain of g(y), and this will be the range of f(x).

If you can't seem to solve for x, then try graphing the function to find the range.

I WILL MAKE BRIANLIEST PERSON BRIANLY. HAALP!!!!!

Answers

Answer:

she did not randomly select enough students

Step-by-step explanation:

there is too much of an area for mistakes in this experiment as the teacher could unknowingly have a bias in terms of choosing a female student.

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Answers

63$ 4.5x1400/100 he made 63$ off the 1400$

Helppp please 4-6 !!!

Answers

Answer: -2 ( negative two)

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