What is the square 16/15 in simplest radical form?

Answers

Answer 1

Answer:

Answer:

To start off, this fraction needs to be rationalized; you can't have a radical in the denominator. So, you multiply both the numerator & denominator by the same number (so as to not mess up the proportion of numerator:denominator; it's like multiplying by 1) & get the radical out of the denominator. What number would that be? sqrt5.

So we have (sqrt6/sqrt5)•(sqrt5/sqrt5).

To simplify that, we get (sqrt6•sqrt5)/(sqrt5•sqrt5).

This can be rewritten as:

sqrt(6•5)/sqrt(5•5)

= sqrt30/sqrt25

Now, sqrt25 = 5, so that problem is solved as such:

sqrt30/5

I'm thinking sqrt30 can't be simplified any further. If it can, do so.

Hope this helps!

Step-by-step explanation:

The measure of angle VSU is 35°.

Step-by-step explanation:

We know that the arc VST is 220°.

This means arc VUT is 140°, because it's the difference between the total arc 360° and 220°.

Also, we know that segments UV and UT are congruent, that means their arcs are also congruent. So, the measure of arc VUT can be equally divided, that means arc VU is 70°.

Now, the inscribed angle theorem states that the angle formed by two intersecting chords is half of its subtended arc.

$\angle VSU = (1)/(2) arc(VU)=(1)/(2)(70\°) \n \angle VSU = 35\°$

Therefore, the measure of angle VSU is 35°.

Pj will begin her cake deliveries at 12:20. She asked me to remind her 30 minutes befor she has to leave. What time should I remind pj about her deliveries

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According to the information given, using subtraction of time involving minutes, you should remind pj about her deliveries at 11:50 AM.

She will begin her deliveries at 12:20 PM.

You have to remind her 30 minutes before that.

20 minutes before is 12 PM.

Before 12 PM, the times are AM.

10 minutes extra have to be subtracted(20 already have), 60 subtracted by 10 is 50, hence:

You should remind pj about her deliveries at 11:50 AM.

To learn more about operations involving hours and minutes, you can take a look at brainly.com/question/25169144

choose the equation below that represents the line that passes through the point (−2, −1) and has a slope of 5. (5 points) y − 1 = 5(x − 2) y 1 = 5(x 2) y 2 = 5(x 1) y − 2 = 5(x − 1)

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Equation of a line;
y=mx+c
m=5
y=5x+c
Replacing for x and y using point (-2, -1)
-1=5(-2)+c
-1=-10+c
c=-1+10
c=9
y=5x+9

Stonehenge II in Hunt, Texas, is a scale model of the ancient construction in Wiltshire, England.The scale of the model to the original is 3 to 5 . the Alter Stone of the original construction is 4.9 meters tall. write and solve a porportion to find the height of the model of the Alter Stone

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Let the height of the model of the Alter Stone be h.
Then, 3/5 = h/4.9
h = (3 x 4.9)/5 = 2.94

Therefore, the height of the Alter Stone is 2.94 meters

Car B was driven at the speed of 48 miles per hour.how long was the test.

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One hour... that's what I think

Your answer is 1 hour.

Hope this helps.

The yearbook club had a meeting. The meeting had 15 people, which is three-fifths of the club. How many people are in the club?

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25.
For me, I just did 15 divided by 3, which equals to 5. So.. You do 5 x 5 to find out how many people there are in the club in total.

Final answer:

The question is about finding the total number of people in the yearbook club given that 15 people represent three-fifths of the total. By using a proportion, we find that the yearbook club has 25 people.

Explanation:

This is a proportional relationship problem in mathematics. You are given that 15 people represent three-fifths (or 3/5) of the total number of people in the yearbook club. To find the total number of people in the club, you set up the proportion: 15 is to 3 and X is to 5.

Then, cross multiply and solve the equation for X. 3*X = 15*5, therefore X = 75/3 = 25. So, there are 25 people in the yearbook club.