Help me with this problem, thanks​
help me with this problem, thanks​ - 1

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Answer 1
Answer:

: no, ur so rude. why do u have to be so mean ....


Related Questions

Find the highest common factor (HCF) of 90 and 126
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1. In order to get more female customers, a new clothing store offers free gourmet coffee and pastry to its customers. The average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260. Use this sample information to construct a 95% confidence interval for the average daily revenue. The store manager believes that the coffee and pastry strategy would lead to an average daily revenue of $1,200. Is the manager correct based on the 95% confidence interval?

Consider the initial value problem:y' + 5/3y =1 - 1/5t, y(0)= yo

What equation expresses the requirement that the solution touches the t-axis?
a. y(t)= 0
b. y'(t)= 0
c. y''(t)= 0

Answers

Answer:

a. y(t) = 0

Step-by-step explanation:

There are two axis on the graph. One is x-axis which is horizontal line on the graph and the other is y-axis which is vertical side of the graph. The point where x-axis and y-axis meet is origin which has value 0. The equation to write the points of the graph is represented by y(x) = 0. In the given equation there is t variable used in the values.

Final answer:

The requirement that the solution of the given initial value problem 'touches' the t-axis is represented by the equation y(t) = 0. This is because the output of the function is zero at that specific value of t. Contrastingly, y'(t) = 0 and y''(t) = 0 indicate conditions of slope and rate of slope change.

Explanation:

In the given initial value problem, the requirement that the solution 'touches' the t-axis is represented by the equation y(t) = 0. This is because when the function Touches the t-axis, the y-value (output of the function) is zero for that specific value of t.

It's worth noting that y'(t) = 0 and y''(t) = 0 represent the conditions where the slope of a function is zero (which corresponds to a localminimum or maximum), and where the rate of change of the slope is zero (which can indicate a point of inflection), respectively.

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Zoe is helping her grandmother freeze strawberries from the family garden. They have 20 pounds of strawberries to freeze. If they put 1.25 pounds of strawberries into each freezing container, how many containers will they fill?

Answers

Answer:

16

Step-by-step explanation:

1 Container = 1.25 Pounds

? Container = 20 Pounds

  • (Simple crisscross multiplication) 1x20Pounds = 20 = 16 Containers

1.25Pounds 1.25

The blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of and a standard deviation of . ​(All units are 1000 ​cells/​L.) Using the empirical​ rule, find each approximate percentage below. a. What is the approximate percentage of women with platelet counts within standard of the​ mean, or between and ​?
b. What is the approximate percentage of women with platelet counts between and ​?

Answers

Answer:

(a) Approximately 95% of women with platelet counts within 2 standard deviations of the​ mean.

(b) Approximately 99.7% of women have platelet counts between 65.2 and 431.8.

Step-by-step explanation:

The complete question is: The blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 248.5 and a standard deviation of 61.1. ​(All units are 1000 ​cells/mu​l.) using the empirical​ rule, find each approximate percentage below.

a. What is the approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 126.3 and 370.7​?

b. What is the approximate percentage of women with platelet counts between 65.2 and 431.8​?

We are given that the blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 248.5 and a standard deviation of 61.1.

Let X = the blood platelet counts of a group of women

The z-score probability distribution for the normal distribution is given by;

                             Z  =  (X-\mu)/(\sigma)  ~ N(0,1)

where, \mu = population mean = 248.5

            \sigma = standard deviation = 61.1

Now, the empirical rule states that;

  • 68% of the data values lie within 1 standard deviation away from the mean.
  • 95% of the data values lie within 2 standard deviations away from the mean.
  • 99.7% of the data values lie within 3 standard deviations away from the mean.

(a) The approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 126.3 and 370.7 is given by;

As we know that;

P(\mu-2\sigma < X < \mu+2\sigma) = 0.95

P(248.5 - 2(61.1) < X < 248.5 + 2(61.1)) = 0.95

P(126.3 < X < 370.7) = 0.95

Hence, approximately 95% of women with platelet counts within 2 standard deviations of the​ mean.

(b) The approximate percentage of women with platelet counts between 65.2 and 431.8​ is given by;

Firstly, we will calculate the z-scores for both the counts;

z-score for 65.2 = (X-\mu)/(\sigma)

                           = (65.2-248.5)/(61.1) = -3

z-score for 431.8 = (X-\mu)/(\sigma)

                           = (431.8-248.5)/(61.1) = 3

This means that approximately 99.7% of women have platelet counts between 65.2 and 431.8.

Final answer:

Using the empirical rule, approximately 68% of values fall within 1 standard deviation from the mean in a bell-shaped distribution. For ranges 2 or 3 standard deviations from the mean, the respective approximate percentages are 95% and 99.7%.

Explanation:

The question refers to the Empirical rule, which in statistics, is also known as the Three-sigma rule or the 68-95-99.7 rule. This rule is a shortcut for remembering the proportion of values in a normal distribution that are within a given distance from the mean: 68% are within 1 standard deviation, 95% are within 2 standard deviations, and 99.7% are within 3 standard deviations.

Without given specific values for the mean or standard deviations, we can discuss the problem in a general sense:

  • For part a, the percentage of women with platelet counts within 1 standard deviation from the mean is approximately 68% under the Empirical rule.
  • For part b, it depends on how many standard deviations from the mean the range mentioned lies. If it refers to two standard deviations from the mean, then 95% of women would fall into this range, if it refers to three standard deviations, then approximately 99.7% would be the case.

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Please explain as well 4x+3y=24 6x+5y=346x+5y=34 x= y=

Answers

Answer:

x = 9 y = -4

Step-by-step explanation:

4x + 3y = 24 . (-5) ------> -20x -15y = -120 (A)

6x + 5y = 34 . (3) -------> 18x + 15y = 102 (B)

(A) + (B) ----------> -2x = -18 ---------> x = 9

4.9 + 3y = 24

3y = 24 - 36

3y = -12

y = -4

For a particular event, 845 tickets were sold for a total of $4162. If students paid $4 per ticket and non students paid $6 per ticket, how many student tickets were sold?

Answers

For a particular event, 812 tickets were sold for a total of $1912. If students paid $2 per ticket and nonstudents paid $3 per ticket

Suppose that the value of a stock varies each day from $12.82 to $33.17 witha uniform distribution.
Find the third quartile; 75% of all days the stock is below what value?

Answers

Answer:

$28.08

Step-by-step explanation:

$33.17 - $12.82 = $20.35

75% of $20.35 = $15.26

$15.26 + $12.82 = $28.08