A bookmark is 9 centimeters tall and 2 centimeters wide what is its area

Answers

Answer 1
Answer:

Answer:

length of book mark =9cm

breadth of bookmark=2cm

area of bookmark=length×breadth

=9cm×2cm

=18cm answer

Answer 2
Answer:

Final answer:

The area of the bookmark is found by multiplying its length (9 cm) by its width (2 cm), giving a total of 18 square centimeters.

Explanation:

The area of a shape is calculated by multiplying the length by the width. In this case, the length of the bookmark is 9 centimeters and the width is 2 centimeters. So, the area of the bookmark will be 9 cm multiplied by 2 cm which equals to 18 square centimeters.

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If 3 1/2 pounds of bananas cost $1.96 how much would one pound cost

Answers

It would simply be 1.96 divided by 3.5. It would be 56 cents per pound.
3 1/2 ib = $1,96  
(7)/(2) * (2)/(7) ib = (196)/(100) * (2)/(7) \n \n 1ib = (28)/(100) * (2)/(1) \n \n 1ib = (56)/(100) = 0,56

Answer 1 pound of bananas costs $0.56 

A circle has a circumference of 196π
What is the radius of the circle?

Answers

Circumference=2πr
196π=2πr. Divide both sides by 2π so the answer is 98

Find the area of the parallelogram. pick one of these30 sq cm
40 sq cm
12 sq cm
17 sq cm

Answers

Answer:

The area of the parallelogram is 40.

Step-by-step explanation:

You multiply the base by the height:

4*10= 40

40 sq
Explanation: I took the test

What is the next number in this sequence?

2, 3, 5, 8, 12, ___

Answers

the answer is 17 ..
2+1 +3 
3+2=5
5+3=8
8+4=12
12+5=17

How to i find the missing 2 angles

Answers

Answer:

therefore, x is 71 degrees

Step-by-step explanation:

we know that the exterior angle is 142 degrees.

we also know that we have to find x, which is labeled two times as an interior triangle (in the same triangle), so they must be the same degree.

there are different ways to solve this but the easiest way is this:

exterior angle = opposite interior angle 1 + opposite interior angle 2

142 degrees = x + x

142 degrees = 2x

142/2 = x

x = 71

therefore, x is 71 degrees

Cos A = square root 21 divided by 5 and sin A = 2/5. What is the exact value of cos 2A?

Answers

cos\alpha=(√(21))/(5);\ sin\alpha=(2)/(5)\n\n\ncos2\alpha=cos^2\alpha-sin^2\alpha\n\ncos^2\alpha=\left((√(21))/(5)\right)^2=(21)/(25)\n\nsin^2\alpha=\left((2)/(5)\right)^2=(4)/(25)\n\ncos2\alpha=(21)/(25)-(4)/(25)=(17)/(25)