PHYSICS HIGH SCHOOL

An engine raises 100kg of water through a height of 60m in 20s. what is the power of the engine​

Answers

Answer 1
Answer:

Answer:

the answer is 3000

Explanation:

power=mass×gravity×height or (divided by /Time)

so 100kg×10×60m/20s

=60,000/20

=3000joule

if I am wrong correct me

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What determines all the star's properties such as its temperature, size, brightness and life span?a. Weight b. Mass c. Diameter d. Luminosity

Answers

The correct answer to the question that is stated above is letter d. Luminosity.
Luminosity is the total energy that star produce in one second, depending on both the radius of the star and on its surface temperature. Thus, all the star's properties such as its temperature, size, brightness and life span is determined by its luminosity.

a string is attached to the rear-view mirror of a car. a ball is hanging at the other end of the string. the car is driving around in a circle, at a constant speed. which of the following lists gives all of the forces directly acting on the ball?

Answers

The correct answer for the question that is being presented above is this one: "b. tension, gravity and centripetal force." It gives all of the forces directly acting on the ball.

Here are the following choices:
a. Tension and gravity 
b. tension, gravity and centripetal force 
c. Tension 
d. Tension gravity centripetal force and frictional force

C. The driver is looking at her phone and has a total reaction time of 4.6 seconds as the car is moving at a constant speed of 11 m/s. If the driver slams on her brakes and slows down at a rate of -8.2 m/s2, what is the stopping distance for the car in this situation

Answers

Answer:

The stopping distance for the car when the driver slams on her brakes is 7.38 m.

Explanation:

The distance traveled for the car after stopping can be found using the following equation:

v_(f)^(2) = v_(0)^(2) + 2ad

Where:

vf is the final speed = 0 (it stops)

v₀ is the initial speed = 11 m/s

a is the acceleration = -8.2 m/s²

d is the distance =?

When the driver slams on her brakes the distance traveled is:

d = -(v_(0)^(2))/(2a) = -((11 m/s)^(2))/(2*(-8.2 m/s^(2))) = 7.38 m

 

Therefore, the stopping distance for the car when the driver slams on her brakes is 7.38 m.

I hope it helps you!                                        

A 9.0 volt battery is connected to four resistors in a parallel circuit. The resistors have 7.0 Ω, 5.0 Ω, 4.0 Ω, and 2.0 Ω respectively. What is the total current in the circuit?

Answers

series,effective resistance =R₁+R₂+R₃...
parallel,effective resistance 1/R=1/R₁ +1/R₂ +1/R₃...
 
Here,effective resistance 1/R =1/7 +1/5+ 1/4+1/2  
                                           =1.092
                                       R = 1/1.092 =0.915Ω
voltage V=9 V 
current I=V/R
           I=9 / 0.915
            =9.83 A
parallel resistance = (1)/(7) + (1)/(5) + (1)/(4) + (1)/(2)
=(140)/(153)

now , V= 9V
V = IR
I = (V)/(R)
I = (9)/(140) x 153
I = 9.835714 A

Which of these is not a conservative force and does not have a form of potential energy connected with it?

Answers

It sounds a if there should be some types of forses to choose... Anyway, I have got what you need and the forse which is not a conservative force and does not have a form of potential energy connected with it is  friction. 

A sound-producing object is moving toward an observer. The sound the observer hears will have a frequency ___ that actually being produced by the object. higher than
lower than
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Answers

The answer is higher than.
A sound-producing object is moving toward an observer. The sound the observer hears will have a frequency higher than that actually being produced by the object.

Why?
As the source of the waves is moving toward the observer, each of the successive wave crest is emitted from a position closer to the observer than the previous wave.
Thus each wave takes slightly less time to reach the observer than the previous wave. So, the time between the arrival of successive wave crests at the observer is reduced, increasing the frequency. 
Answer: higher than 

This phenomenon is known as the Doppler Effect. It occurs when a sound producing object is approaching towards an observer, it can be noticed that the sound is higher than what it really is. The sound usually fades as the object passes by.
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