Using translation concepts, the coordinates of triangle A'B'C' are given as follows:
A' (11, 12), B' (5,-10), C (-2, 2).
A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s range(involving values of y) or in it’s domain(involving values of x). Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis, or rotations of a degree measure around the origin.
For this problem, the translation rule is given as follows:
(x,y) -> (x + 3, 2y).
Applying the rule to each vertex, we have that:
Hence the coordinates of triangle A'B'C' are given as follows:
A' (11, 12), B' (5,-10), C (-2, 2).
More can be learned about translation concepts at brainly.com/question/4521517
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The transformed coordinates of triangle ABC using the rule (x,y) - (x + 3,2y) are A' (11,12), B' (5,-10), and C' (-2,2).
To solve the problem, we apply the given transformation rule (x,y) - (x + 3,2y) to each vertex of triangle ABC. Thus, vertex A (8,6) will transform into A' (8+3,2*6), B (2,-5) will become B' (2+3,2*-5), and C (-5,1) will transform into C' (-5+3,2*1). Let's calculate:
A'(8+3, 2*6) = A' (11,12). B' (2+3, 2*-5) = B' (5,-10). C' (-5+3, 2*1) = C' (-2,2)
So, the coordinates of triangle A'B'C' after the transformation are A'B'C': A' (11,12), B' (5,-10), C' (-2,2).
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The rate of increase of the radius when the radius of the cone is 4 cm is approximately 0.299 cm/s. This was calculated by using the derivative of the volume of a cone with respect to its radius, with the height of the cone always being three times the radius.
The subject of this question relates to the rate of change in the context of the volume and radius of a cone. The volume of a right circular cone is given by the formula V = 1/3πr²h. Given that the height is always three times the radius, we can substitute h = 3r into the formula, which gives V = 1/3πr³ * 3 = πr³.
The rate of change of the volume with respect to time (dV/dt) is given as 45 cm³/s. We can set up an equation using the derivative of the volume with respect to the radius and the relation dV/dt = (dV/dr)(dr/dt). Calculating the derivative of the volume with respect to the radius, we find that dV/dr = 3πr². Substituting the provided values into our relation gives us 45 = 3π(4)²*dr/dt. Solving for dr/dt, we find the rate of change of the radius to be approximately 0.299 cm/s to 3 significant figures.
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Answer:
21
Step-by-step explanation:
x =4
a. 4, -2
b. 4, 3
c. 4, 4
d. 4, -3