Answer:
See attachment
Step-by-step explanation:
See attachment
Answer:
Step-by-step explanation:
The equation of the line goes as , where m is slope and b is y-intercept. Since we are already given slope and a point (x,y), we can plug those values in and solve for b.
[multiply]
[add both sides by 20/3]
Now, we can plug in all the values together to get .
The equation of the line with the slope -2/3 that passes through the point (10, -4) is y = -2/3x + 8/3.
The subject of this question is the equation of a straight line, specifically how to write the equation of a line with a given slope and passing through a specific point. Given the slope, m = -2/3, and the point P(10, -4), we can use the point-slope form of the line which is y - y1 = m(x - x1). Substituting the given values into the formula, we get y - (-4) = -2/3(x - 10). Simplifying this we get y + 4 = -2/3x + 20/3. Even further simplification leads to the equation of the line y = -2/3x + 20/3 - 12/3, finall getting y = -2/3x + 8/3.
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When each member or non member takes 6 classes, the cost to each of them will be the same.
For members: 6 (membership) + 6(5) = 36
For nonmembers, 6 classes cost 6(6) = 36
So, 6 classes
this can also be explained as c on edg
a. -10n+20
b. -10n+19
c. 36n-36
d. -8n+56