Solve 3sqrt(x) = 8/(sqrt(9x - 32)) + sqrt(9x - 32)​

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

3√(x)=(8)/(√(9x-32))+√(9x -32)\n\n\n3√(x)=(8*√(9x-32))/((√(9x-32))*(√(9x-32)))+√(9x-32)\n\n3√(x)=(8*√(9x-32))/(9x-32)+√(9x-32)\n\n\n3√(x)=(√(9x-32))((8)/(9x-32)+1)\n\n(3√(x))/(√(9x-32))=(8+9x-32)/(9x-32)\n\n(3√(x))/(√(9x-32))=(9x - 24)/(9x-32)\n\nTake \ square\n\n((3√(x))/(√(9x-32)))^(2)=((9x-24)/(9x-32))^(2)\n\n(9x)/(9x-32)=((9x-24)^(2))/((9x-32)^(2))\n\n

9x*(9x - 32) = (9x- 24)²

9x*9x - 9x*32 = 81x² - 2*9x*24 + 576

81x² - 288x = 81x² - 432x + 576

81x² - 288x - 81x² + 432x - 576 = 0

81x² - 81x² - 288x + 432x - 576 = 0

144x - 576 = 0

144x = 576

x = 576/144

x =4

Answer 2
Answer:

\huge \color{gray}{ \tt{answer}}

x = 4

Step-by-step explanation:

3 √(x)  =  (8)/((9x - 32))  +  √((9x - 32))

  • move theexpressionto theleft

3 √(x)  -  (8)/( √(9x - 32) )  -  √(9x - 32)  = 0

  • transform the expression

(3 √((9x - 32 x)) - 8 -  √(9x - 32) )/( √(9x - 32) )

  • set the numerator

3  √((9x - 32)x)   - 8 - (9x - 32) = 0

  • remove the parentheses

3 \sqrt{9 {x}^(2)  - 32x}  + 24 - 9x = 0

  • move the expression to the right

3 \sqrt{9 {x}^(2) - 32x }   - 24 + 9x

  • divide both sides

\sqrt{9 {x}^(2) - 32x }  =  - 8 + 3x

  • simplify the expression

9 {x}^(2)  - 32x = 9 {x}^(2)  - 48x + 64

  • cancel equal terms

- 32x =  - 48x + 64

  • move the variable to the left

- 32x =   +  48x = 64

  • collect like terms

16x = 64

  • divide both sides

= \:  \:  x = 4

  • check thesolution

3 √(4)  =  (8)/( √(9 * 4 - 32) )  +  √(9 * 4 - 32)

  • simplify

6 = 6

  • so the solutionis

≈ \:  \: x = 4

\huge \color {cyan}{ \tt{hope \:  \: it \:  \: helps}}


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Which number line represents the solutions to |x + 4| = 2?

Answers

Answer:

The solution is represented by  the first number line, wich has the solutions x=-6 and x=-2.

Step-by-step explanation:

We have an absolute value function for the equation. This means that we should have two differents solution in the real number line. As the equation is

|x+4|=2

when we clear out the absolute value, we will have two possible solutions:

x+4=2

and

-(x+4)=2

now we clear x from both equations

x+4=2 \Leftrightarrow x=2-4 \Leftrightarrow x=-2

-(x+4)=2 \Leftrightarrow -x-4=2 \Leftrightarrow -2-4=x \Leftrightarrow x=-6

Then, we have that x=-2 and x=-4 are the solutions for the equation, and therefore the number line that represents the solution is the first one, where the points -6 and -2 are highlighted.

the first number line

given | x + 4 | = 2

removing the bars from the absolute value gives

x + 4 = 2 or x + 4 = - 2

x = 2 - 4 or x = - 2 - 4

x = - 2 and x = - 6 ← solutions

these are indicated on the number line by a solid circle at - 2, - 6


The Ericsson method is one of several methods claimed to increase the likelihood of a baby girl. In a clinical​ trial, results could be analyzed with a formal hypothesis test with the alternative hypothesis of pgreater than​0.5,which corresponds to the claim that the method increases the likelihood of having a​ girl, so that the proportion of girls is greater than 0.5. If you have an interest in establishing the success of the​ method, which of the following​ P-values would you​ prefer: 0.999,​ 0.5, 0.95,​ 0.05, 0.01,​ 0.001? Why?

Answers

Answer:

0.001

Step-by-step explanation:

Here, the aim is to support the null hypothesis, Ha. Where Ha: p > 0.5. Which means we are to reject null hypothesis H0. Where H0: p = 0.5.

The higher the pvalue, the higher the evidence of success. We know If the pvalue is less than level of significance, the null hypothesis H0 is rejected.

Hence the smallest possible value 0.001 is preferred as the pvalue because it corresponds to the sample evidence that most strongly supports the alternative hypothesis that the method is effective

Hi I need help with the one that is circle thank you

Answers

Answer:

B1: +6 (to get to plus six you would have to pass negative one so really it's seven)

B2: they are the same distance

B3: -7

B4: +7  

<3 have a good day :)

Step-by-step explanation:

Answer:

hope this helped! Can I get brainliest? :)) please?

Step-by-step explanation:

1. +6 is the answer because it is 8 units away from -2

2.  both are the same distance from -2

3.  -7 is the answer because it is 5 units away from -2

4. +7 is the answer because it is 9 units away from -2

The marks on a combination lock are numbered 0 to 39. If the lock is at mark 19, and the dial is turned one mark clockwise, it will be at mark 18. If the lock is at mark 19 and turned 137 marks clockwise, at what mark will it be

Answers

Answer:

Mark 2  

Step-by-step explanation:

There are 40 marks on the lock.

Every full turn of 40 marks, the lock will come back to mark 19.

137/40 = 3R17

You can make three full turns (which is equivalent to doing nothing), and then you must move 17 more marks.

19 - 17 = 2

The lock will be at mark 2.

If the lock is at mark 19 and turned 137 marks clockwise, it will be at mark 2.

What is combination lock?

Combination lock is opened by rotating a set of number dials or marks graduated in a sequence.

The marks on a combination lock are numbered 0 to 39. If the lock is at mark 19, and the dial is turned one mark clockwise, it will be at mark 18. If the lock is at mark 19 and turned 137 marks clockwise,

137 = 40a +b where b<40

Divide 137 by 40, so we get the quotient 3 i.e., a =3.

Substitute a = 3 , the value of b is

b = 17

If the lock is at mark 19 and turned 137 marks clockwise, it will be at mark,

19-17 = 2

Thus, If the lock is at mark 19 and turned 137 marks clockwise, it will be at mark 2.

Learn more about combination lock.

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What would the measurement at the top be?

Answers

Hopes this helps please correct me if I am wrong:

Answer: 6cm
6cm, the reason for that is because of the invisible line that says 6cm if that line is the same length as the top; which it is, it would also be 6cm

So in conclusion the answer would be 6cm.

Hope this helps! Have a good one!❤️

PLZ HELP ASAP SOLID GEOMETRY

Answers

The correct choice (B)
By slicing the triangular prism with a plane parallel to the equilateral base
that will produce an equilateral triangle cross section
see the attached figure