Simplify plzzzzzzzzzzzzzzz

Answers

Answer 1

Answer:

the answer is the first fraction

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What is the slope of the line that passes through the pair of points? (1, 7), (10, 1)a. –2/3
b. 3/2
c. 2/3
d. –3/2

Answers

slope=(y2-y1)/(x2-x1)
(x,y)
x1=1
y1=7
x2=10
y2=1

slope=(1-7)/(10-1)=-6/9=-2/3
answer is A

Hello!

Answer:

A. -2/3

*The answer must have a fraction.*

Step-by-step explanation:

Slope: $(Y^2-Y^1)/(X^2-X^1)=(rise)/(run)$

$(1-7=-6)/(10-1=9)=(-6)/(9)=(-6/3)/(9/3)=(-2)/(3)$

Slope is -2/3

Answer: -2/3

Hope this helps!

Thanks!

-Charlie

Have a great day!

Can anyone help me Factor.
81-25x^2

Answers

that is difference of two squares so the answer is (9-5x)(9+5x)

Mike can cut a 40 foot by 20 foot yard with a push mower in 25 minutes. At this rate, how many more minutes would it take him to cut a 40 foot by 30 foot yard?

Answers

The time required to cut the area of 40 feet by 30 feet will be 37.5 minutes.

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that Mike can cut a 40-foot by 20-foot yard with a push mower in 25 minutes. The time required for 40 foot x 30-foot area will be calculated as:-

40 x 20 foot yard = 25 minutes

800-foot yard = 25 minutes

1 foot yard = 25 / 800

( 40 x 30 ) foot yard = ( 25 / 800 ) x ( 40 x 30 )

1200 foot yard = ( 25 / 800 ) x ( 1200)

1200-foot yard = 37.5 minutes

Therefore, the time required to cut the area of 40 feet by 30 feet will be 37.5 minutes.

To know more about an expression follow

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area of the yard is 40 .20 = 800sq ft
time taken = 25 mins
time taken to mow 1sq ft = 25/800 mins
time taken to mow 40 .30 =1200sq ft = ( 25 .1200)/800 = 371/2 mins
thus the extra time taken will be 371/2-25 = 121/2 mins

54+(x-4)=x ............